在 sql 语句中用 yes 和 not 计算值答案

【问题标题】：count values with yes and not in sql statement在 sql 语句中用 yes 和 not 计算值
【发布时间】：2016-03-05 23:13:31
【问题描述】：

我有一张表格，里面有这样的数据：

 USER  NAME     Timestamp               EXECUTED    CLOSED
1 user1 JOHN DOE 2015-11-23 12:50:45         Yes       Yes
2 user1 JOHN DOE 2015-11-23 12:52:35         Yes       Yes
3 user1 JOHN DOE 2015-11-23 12:53:52         Yes       Yes
4 user1 JOHN DOE 2015-11-23 12:54:59         Yes       Yes
5 user1 JOHN DOE 2015-11-23 12:56:04         Yes       Yes
6 user1 JOHN DOE 2015-11-23 18:09:37         Yes       No
7 user1 JOHN DOE 2015-11-23 18:15:46         Yes       Yes
8 user1 JOHN DOE 2015-11-23 18:17:02         Yes       Yes

我想准备一份这样的报告：

USER   NAME      EXECUTED  CLOSED  NOTCLOSED
user1  JOHN DOE    8         7         1

我尝试过这样的事情：

SELECT USER, NAME, Timestamp, count(EXECUTED), count(CLOSED) 
FROM table 
WHERE Timestamp LIKE "2015-11-23%" 
AND EXECUTED = "Yes" 
AND CLOSED = "Yes"

但在这种情况下的结果永远显示：

EXECUTED    CLOSED
8           8

当我有 1 条 Closed = No 的记录时。我知道当我计算列 EXECUTED 和 CLOSED 时，我无法使用 WHERE = YES/NO 正确评估，因为数据类型更改为整数，但我找不到合适的解决方案。

其他事情：如何向“NO CLOSE”列显示正确的值？（EXECUTED 和 CLOSED 的区别）

【问题讨论】：

标签： sql sqlite aggregate-functions

【解决方案1】：

这样的事情应该可以工作：

;WITH counts AS (
    SELECT USER
          ,NAME
          ,Timestamp
          ,SUM(CASE WHEN EXECUTED = "YES" THEN 1 ELSE 0 END) AS NumExecuted
          ,SUM(CASE WHEN CLOSED = "YES" THEN 1 ELSE 0 END) AS NumClosed
    FROM table 
    WHERE Timestamp LIKE "2015-11-23%" 
)
SELECT USER
      ,NAME
      ,Timestamp
      ,NumExecuted
      ,NumClosed
      ,NumExecuted - NumClosed AS NumOpen
FROM counts

【讨论】：

为什么要在 WITH 前面加分号？
COUNT() 计算所有非 NULL 值，因此它也很乐意计算 0 值。您需要 NULL 或不同的聚合函数。
@CL 是的，当然。我的意思是 SUM，而不是 COUNT（已编辑）。我出于习惯添加了分号，以确保在启动 CTE（公用表表达式）之前终止任何先前的语句。不过，在这个例子中完全没有必要。
那为什么要把它留在那里（并省略终止分号）？
查看 Aaron Bertrand 对同一问题的回复：dba.stackexchange.com/a/23374

【解决方案2】：

select user, name,
    sum(case when executed = 'Yes' then 1 else 0 end) as executed,
    sum(case when closed = 'Yes' then 1 else 0 end) as closed,
    sum(case when executed = 'Yes' and closed = 'No' then 1 else 0 end) as notclosed
from user
group by user, name

【讨论】：

完美运行！谢谢！！