【发布时间】:2019-05-17 07:42:30
【问题描述】:
我编写了一个大型 MySQL 查询来检索给定用户的所有权限,最近发现由于 ONLY_FULL_GROUP_BY 模式,这在较新版本的 MySQL 中不起作用。
检索给定用户的所有授予权限的查询是:
SELECT
`name`,
`display_name`,
`description`
FROM(
SELECT * FROM (
SELECT
`p`.`id`,
`p`.`name`,
`p`.`display_name`,
`p`.`description`,
MAX(`r`.`priority`),
IFNULL(`up`.`is_granted`, `rp`.`is_granted`) AS `is_granted`
FROM `permissions` AS `p`
LEFT JOIN `user_permissions` AS `up`
ON `up`.`permission` = `p`.`id`
AND `up`.`user` = 1
LEFT JOIN `role_permissions` `rp`
ON `rp`.`permission` = `p`.`id`
AND `rp`.`role` IN(
SELECT
`ur`.`role`
FROM `user_roles` AS `ur`
WHERE `ur`.`user` = 1
)
LEFT JOIN `roles` AS `r`
ON `r`.`id` = `rp`.`role`
GROUP BY `r`.`priority` DESC, `rp`.`permission`, `up`.`permission`
) AS `res`
GROUP BY `res`.`id` ASC
) AS `res`
WHERE `res`.`is_granted` = 1
这会在启用标志 ONLY_FULL_GROUP_BY(默认启用)的较新 MySQL 安装上产生以下错误:SQL Error (1055): Expression #5 of SELECT list is not in GROUP BY clause and contains nonaggregated column 'res.MAX(r.priority)' which is not functionally dependent on columns in GROUP BY clause; this is incompatible with sql_mode=only_full_group_by。
我尝试完全重写查询以提高效率并启用标志,但它并没有达到与第一个查询相同的目标。
SELECT
u.id AS user_id,
u.email AS user_email,
up.permission AS user_permission_id,
up.is_granted AS user_permission_is_granted,
upp.name AS user_permission_name,
upp.display_name AS user_permission_display_name,
upp.description AS user_permission_description,
ur.role AS role_id,
urr.name AS role_name,
urr.display_name AS role_display_name,
urr.priority AS role_priority,
urp.permission AS role_permission_id,
urp.is_granted AS role_permission_is_granted,
urpp.name AS role_permission_name,
urpp.display_name AS role_permission_display_name,
urpp.description AS role_permission_description
FROM users u
LEFT JOIN user_permissions up
ON up.user = u.id
LEFT JOIN permissions upp
ON upp.id = up.permission
LEFT JOIN user_roles ur
ON ur.user = u.id
LEFT JOIN roles urr
ON urr.id = ur.role
LEFT JOIN role_permissions urp
ON urp.role = ur.role
LEFT JOIN permissions urpp
ON urpp.id = urp.permission
WHERE u.id = 1
我该怎么做?我已经尝试了几次,但无法真正看到在不禁用 ONLY_FULL_GROUP_BY 模式的情况下只返回具有最高优先级的行的方法。
我是否应该只使用较新的查询并在应用程序代码中而不是在 SQL 查询中应用角色优先级?
Here is a DBFiddle with database structure and query.
鉴于上述 DBFiddle 中的数据,我希望结果集如下所示:
| user_id | user_email | permission_id | permission_name | permission_display_name | permission_description | is_granted |
| ------- | ----------------- | ------------- | --------------- | ----------------------- | -------------------------------------------------- | ---------- |
| 1 | user1@example.com | 1 | test1 | Test permission 1 | Role permission, should ONLY be granted to user 1 | 1 |
| 1 | user1@example.com | 2 | test2 | Test permission 2 | Role permission, should ONLY be granted to user 1 | 1 |
| 1 | user1@example.com | 3 | test3 | Test permission 3 | Role permission, should ONLY be granted to user 2 | 0 |
| 2 | user2@example.com | 3 | test3 | Test permission 3 | Role permission, should ONLY be granted to user 2 | 1 |
| 1 | user1@example.com | 4 | test4 | Test permission 4 | Role permission, should be granted to user 1 and 2 | 1 |
| 2 | user2@example.com | 4 | test4 | Test permission 4 | Role permission, should be granted to user 1 and 2 | 1 |
| 1 | user1@example.com | 5 | test5 | Test permission 5 | User permission, granted to user 1 | 1 |
| 2 | user2@example.com | 6 | test6 | Test permission 6 | User permission, granted to user 2 | 1 |
我希望权限 ID 3 返回is_granted = 0 而不是不出现在结果集中的原因是因为最初授予用户权限,但后来没有从具有更高优先级的角色 ID 2 授予该权限。
这个问题不是SQL select only rows with max value on a column 的重复问题,因为它特别涉及我应该如何修改我的查询以解决ONLY_FULL_GROUP_BY 模式。
【问题讨论】:
-
为什么
GROUP BY子句中有r.priority列,而SELECT子句中还有MAX(r.priority)? -
请编辑您的问题以包括您的表格的示例数据、结果集的内容应该是什么以及您当前获得的结果集(请参阅meta.stackoverflow.com/questions/333952/…)。
-
感谢@Progman 的回复,我已经用 DBFiddle 更新了问题并希望得到结果集。我相信使用当前的数据结构应该可以实现结果集,只需修改查询即可。
标签: mysql sql aggregate-functions greatest-n-per-group