将新联系人添加到现有联系人组 ews api

Question

在过去的 1½ 天里，我一直在尝试找出这个 API，但现在我正在努力将新创建的联系人添加到现有组中。

我在第一次使用以下代码行运行程序时创建了一个组：

    public static ContactGroup CreateGroup(ExchangeService service)
    {
        // Create a new contact group object.
        ContactGroup myContactGroup = new ContactGroup(service);

        // Give the group a name.
        myContactGroup.DisplayName = "Test Contact Group";

        // Save the group.
        myContactGroup.Save();

        return myContactGroup;
    }

然后我使用以下代码将联系人添加到组：

    public static void AddContactToGroup(ContactGroup myContactGroup, Contact contact)
    {
        myContactGroup.Members.AddContactEmailAddress(contact, EmailAddressKey.EmailAddress2);
        myContactGroup.Update(ConflictResolutionMode.AlwaysOverwrite);

现在我想使用以下代码创建一个新联系人：

    public static Contact tempCont(ExchangeService service)
    {
        Contact contact = new Contact(service);
        contact.GivenName = "Jonas";
        contact.Surname = "Jonassen";
        contact.FileAsMapping = FileAsMapping.SurnameCommaGivenName;
        contact.PhoneNumbers[PhoneNumberKey.HomePhone] = "12345678";
        contact.EmailAddresses[EmailAddressKey.EmailAddress1] = new EmailAddress("jonas@jonassen.dk");

        PhysicalAddressEntry paEntry1 = new PhysicalAddressEntry();
        paEntry1.Street = "123 Main Boulevard";
        paEntry1.City = "Kbh";
        paEntry1.State = "";
        paEntry1.PostalCode = "1200";
        paEntry1.CountryOrRegion = "Denmark";
        contact.PhysicalAddresses[PhysicalAddressKey.Home] = paEntry1;

        contact.Save();

        return contact;
    }

现在我想将此新联系人添加到现有的联系人组中。问题是，我无法掌握“myContactGroup”。我猜我必须找到 ContactGroup 的 ID，或者可能是完全不同的东西。老实说，我不知道如何解决这个问题。任何帮助都会得到帮助！

Answer 1

您需要做的是找到您想要添加联系人的 ContactGroup，例如使用 SearchFilter 来执行此操作，然后只需使用 Add Member 方法将联系人添加到组中，例如

            ItemView ItemView = new ItemView(1);
        SearchFilter cntGroup = new SearchFilter.IsEqualTo(ItemSchema.ItemClass, "IPM.DistList");
        SearchFilter cntGroupName = new SearchFilter.IsEqualTo(ContactGroupSchema.DisplayName, "Test Contact Group");
        SearchFilter sfCol = new SearchFilter.SearchFilterCollection(LogicalOperator.And) { cntGroup, cntGroupName };

        FolderId ContactFolder = new FolderId(WellKnownFolderName.Contacts, "user@domain.com");
        FindItemsResults<Item> fiCntResults = service.FindItems(ContactFolder, sfCol, ItemView);
        if (fiCntResults.Items.Count == 1)
        {
            ContactGroup contactGroup = (ContactGroup)fiCntResults.Items[0];
            Contact Contact2 = new Contact(service);
            Contact2.EmailAddresses[EmailAddressKey.EmailAddress1] = new EmailAddress("blah@blah.dk");
            Contact2.Subject = "Blah";
            Contact2.Save();
            GroupMember gm = new GroupMember(Contact2,EmailAddressKey.EmailAddress1);             

            contactGroup.Members.Add(gm);
            contactGroup.Update(ConflictResolutionMode.AlwaysOverwrite);

        }

干杯 格伦

Answer 2

您可以使用来自其他 stackoverflow 答案的代码，来自注释“//您可以使用以下代码获取 ItemID。”和向下。 https://stackoverflow.com/a/19663185/1289974

Answer 3

感谢塔科曼奥特曼。我同意了 Glen 的回答，但我也设法对您的帖子进行了一些处理，并制定了一个也可以使用的解决方案（只是为了获取 ContactGroup id，我需要将新联系人添加到特定组。代码将看起来像这样，如果我走“你的路”：

    public static ContactGroup FindContactGroup(ExchangeService service, String groupName)
    {
        // Instantiate the item view with the number of items to retrieve from the Contacts folder.
        ItemView view = new ItemView(9999);

        // Request the items in the Contacts folder that have the properties that you selected.
        FindItemsResults<Item> contactItems = service.FindItems(WellKnownFolderName.Contacts, view);

        // Loop through all contacts 
        foreach (Item item in contactItems)
        {
            //Check to see if ContactGroup
            if (item is ContactGroup)
            {
                //Get the contact group
                ContactGroup contactGroup = item as ContactGroup;
                if (contactGroup.DisplayName == groupName)
                {                        
                    return contactGroup;
                }
            }
        }
        return null;
    }

我看到的唯一问题是，这个解决方案会比 Glen 的回答使用更多的内存，因为它必须通过每个联系人。