sqlite INSERT INTO ... WHERE NOT EXISTS 并获取 id？

Question

即使我使用 INSERT INTO ... WHERE NOT EXISTS，是否也可以获得 id？ 如何修改它，它会给我带来插入记录的 id 或已经存在的记录的 id？如果可能的话！

INSERT INTO Timeline (name, ts)
SELECT @name, @ts
WHERE NOT EXISTS (SELECT 1 FROM Timeline WHERE name=@name AND ts = @ts);

我有一列名为“id”的自动增量整数 如何获取 ID 的值？

干杯

Answer 1

您保证 (name,ts) 是唯一的，所以这应该可以解决问题。

INSERT INTO Timeline (name, ts)
SELECT @name, @ts
WHERE NOT EXISTS (SELECT 1 FROM Timeline WHERE name=@name AND ts = @ts);

SELECT id, name, ts from TimeLine
WHERE name=@name AND ts = @ts

Answer 2

你可以使用输出子句：

insert into Timeline output inserted.name 
SELECT @name, @ts
WHERE NOT EXISTS (SELECT 1 FROM Timeline WHERE name=@name AND ts = @ts);

你也可以在更新中做到这一点

update Timeline 
set name = @name
output deleted.name as OLD_NAME, inserted.name as NEW_NAME

已编辑：

运行这个你就明白了：

create table Timeline(
id int not null primary key identity(1,1),
name varchar(50),
ts varchar(50))

insert into timeline output inserted.ID
values ('first record', 'ts') 
--it will show 1


insert into Timeline output inserted.ID 
SELECT 'first record', 'ts'
union select 'new record', 'ts'
WHERE NOT EXISTS (SELECT 1 FROM Timeline WHERE name='first record' AND ts = 'ts')
--ir will show 2 because the 1 already exits