我有一个包含 2 个字段的表格：
身份证名称 -- ------ 1 阿尔法 2 测试版 3 测试版 4 测试版 5 查理 6查理我想按名称、'count' 和一行'SUM'对它们进行分组
名称计数 -------- ----- 阿尔法 1 测试版 3 查理 2 总和 6如何编写查询以在表格下方添加 SUM 行？
【问题讨论】：
SELECT Name, COUNT(*) AS amount, COUNT(*)/total.total * 100 AS percentage, total.total FROM temp, ( SELECT COUNT(*) AS total FROM temp ) AS total GROUP BY NameSee SQLfiddle
我解释这个问题的方式是需要每组答案的小计值。使用PARTITION，小计结果非常简单：
SUM(COUNT(0)) OVER (PARTITION BY [Grouping]) AS [MY_TOTAL]
这是我完整的 SQL 调用的样子：
SELECT MAX(GroupName) [name], MAX(AUX2)[type],
COUNT(0) [count], SUM(COUNT(0)) OVER(PARTITION BY GroupId) AS [total]
FROM [MyView]
WHERE Active=1 AND Type='APP' AND Completed=1
AND [Date] BETWEEN '01/01/2014' AND GETDATE()
AND Id = '5b9xxxxx-xxxx-xxxx-xxxx-xxxxxxxxxxxx' AND GroupId IS NOT NULL
GROUP BY AUX2, GroupId
由此返回的数据如下：
name type count total
Training Group 2 Cancelation 1 52
Training Group 2 Completed 41 52
Training Group 2 No Show 6 52
Training Group 2 Rescheduled 4 52
Training Group 3 NULL 4 10535
Training Group 3 Cancelation 857 10535
Training Group 3 Completed 7923 10535
Training Group 3 No Show 292 10535
Training Group 3 Rescheduled 1459 10535
Training Group 4 Cancelation 2 27
Training Group 4 Completed 24 27
Training Group 4 Rescheduled 1 27
【讨论】：
这里的所有解决方案都很棒，但不一定可以用于旧的 mysql 服务器（至少在我的情况下）。所以你可以使用子查询（我认为它不那么复杂）。
select sum(t1.cnt) from
(SELECT column, COUNT(column) as cnt
FROM
table
GROUP BY
column
HAVING
COUNT(column) > 1) as t1 ;
【讨论】：
我还需要having count(*) > 1。因此，在参考了上述一些查询后，我编写了自己的查询
语法：
select sum(count) from (select count(`table_name`.`id`) as `count` from `table_name` where {some condition} group by {some_column} having count(`table_name`.`id`) > 1) as `tmp`;
例子：
select sum(count) from (select count(`table_name`.`id`) as `count` from `table_name` where `table_name`.`name` IS NOT NULL and `table_name`.`name` != '' group by `table_name`.`name` having count(`table_name`.`id`) > 1) as `tmp`;
【讨论】：
我正在使用 SQL 服务器，以下内容应该适合您：
select cast(name as varchar(16)) as 'Name', count(name) as 'Count' 从表 1 按名称分组 联合所有 选择“总和：”，计数（名称） 来自表1
【讨论】：
SELECT name, COUNT(name) AS count
FROM table
GROUP BY name
UNION ALL
SELECT 'SUM' name, COUNT(name)
FROM table
输出：
name count
-------------------------------------------------- -----------
alpha 1
beta 3
Charlie 2
SUM 6
【讨论】：
Union all？编辑：好的，我因为它的缩进而感到困惑。这只是联合 2 个选择器 :)
试试这个：
SELECT ISNULL(Name,'SUM'), count(*) as Count
FROM table_name
Group By Name
WITH ROLLUP
【讨论】：
你可以使用 ROLLUP
select nvl(name, 'SUM'), count(*)
from table
group by rollup(name)
【讨论】：
从中选择总和 (select count(Col_name) as s from Tab_name group by Col_name with count(*)>1)c
【讨论】：
with cttmp
as
(
select Col_Name, count(*) as ctn from tab_name group by Col_Name having count(Col_Name)>1
)
select sum(ctn) from c
【讨论】：
请如下运行：
Select sum(count)
from (select Name,
count(Name) as Count
from YourTable
group by Name); -- 6
【讨论】：
查询后，在下面运行以获取总行数
select @@ROWCOUNT
【讨论】：
SELECT name, COUNT(name) AS count, SUM(COUNT(name)) OVER() AS total_count
FROM Table GROUP BY name
【讨论】：
Sql server 你可以试试这个。
SELECT ISNULL([NAME],'SUM'),Count([NAME]) AS COUNT
FROM TABLENAME
GROUP BY [NAME] WITH CUBE
【讨论】：
把它当作
select Name, count(Name) as Count from YourTable
group by Name
union
Select 'SUM' , COUNT(Name) from YourTable
【讨论】：
UNION removes duplicate records (where all columns in the results are the same), UNION ALL does not. 那是我使用的 UNION
不指定你使用的是哪个 rdbms
看看这个演示
SELECT Name, COUNT(1) as Cnt
FROM Table1
GROUP BY Name
UNION ALL
SELECT 'SUM' Name, COUNT(1)
FROM Table1
也就是说，我建议由您的表示层添加总数，而不是由数据库添加。
这更像是一个使用 Summarizing Data Using ROLLUP 的 SQL SERVER 版本
SELECT CASE WHEN (GROUPING(NAME) = 1) THEN 'SUM'
ELSE ISNULL(NAME, 'UNKNOWN')
END Name,
COUNT(1) as Cnt
FROM Table1
GROUP BY NAME
WITH ROLLUP
【讨论】：
您可以使用联合来连接行。
select Name, count(*) as Count from yourTable group by Name
union all
select "SUM" as Name, count(*) as Count from yourTable
【讨论】：
您可以尝试按名称分组并计算该组中的 ID。
SELECT name, count(id) as COUNT FROM table group by name
【讨论】：