在 JavaScript 中按 3 个不同的标准排序答案

【问题标题】：Sorting by 3 different criteria in JavaScript在 JavaScript 中按 3 个不同的标准排序
【发布时间】：2021-11-25 04:47:40
【问题描述】：

我正在尝试对下面的列表进行排序，首先按关系（如果它是订阅者，那么它应该是第一个）然后按活动与非活动。活跃应该在不活跃之前然后每个活跃和不活跃应该按年龄降序排序。所以我有这个数组：

[{status: 'Active', BirthDate: '12/31/1960', Relationship:"Friend"},
{status: 'Active', BirthDate: '12/31/1985', Relationship:"Wife"},
{status: 'Inactive', BirthDate: '12/31/1998', Relationship:"Son"},
{status: 'Inactive', BirthDate: '12/31/1996',Relationship:"Daughter"},
{status: 'Active', BirthDate: '12/31/1995', Relationship:"Daughter"},
{status: 'Active', BirthDate: '12/31/1979', Relationship:"Subscriber"},
{status: 'Inactive', BirthDate: '12/31/1999', Relationship:"Son"}
]

结果应该是：

[{status: 'Active', BirthDate: '12/31/1979', Relationship:"Subscriber"},
{status: 'Active', BirthDate: '12/31/1960', Relationship:"Friend"},
{status: 'Active', BirthDate: '12/31/1985', Relationship:"Wife"},
{status: 'Active', BirthDate: '12/31/1995', Relationship:"Daughter"},
{status: 'Inactive', BirthDate: '12/31/1992', Relationship:"Son"},
{status: 'Inactive', BirthDate: '12/31/1996',Relationship:"Daughter"},
{status: 'Inactive', BirthDate: '12/31/1999', Relationship:"Son"}
]

我在下面尝试过，但似乎不起作用：

testlist = testlist.sort((a, b) => (a.Relationship === "Subscriber" ) ? -1 :(a.status === "Active") ? -2 : (b.BirthDate - a.BirthDate) ? -3 : 1);

有没有办法通过在 JavaScript 中使用 .sort 方法来做到这一点？

【问题讨论】：

请添加您尝试过的内容以获得更好的响应
@TusharShahi 我添加了我尝试过的内容
德雷克，你只能在Array.sort()内返回-1、1或0

标签： javascript arrays salesforce javascript-objects lwc

【解决方案1】：

使用Array#sort:

const arr = [ {status: 'Active', BirthDate: '12/31/1960', Relationship:"Friend"}, {status: 'Active', BirthDate: '12/31/1985', Relationship:"Wife"}, {status: 'Inactive', BirthDate: '12/31/1998', Relationship:"Son"}, {status: 'Inactive', BirthDate: '12/31/1996',Relationship:"Daughter"}, {status: 'Active', BirthDate: '12/31/1995', Relationship:"Daughter"}, {status: 'Active', BirthDate: '12/31/1979', Relationship:"Subscriber"}, {status: 'Inactive', BirthDate: '12/31/1999', Relationship:"Son"} ];

const sorted = arr.sort(
  (
    { status: statusA, Relationship: relationshipA, BirthDate: birthDateA }, 
    { status: statusB, Relationship: relationshipB, BirthDate: birthDateB }
  ) => {
    const relationship = (relationshipB === 'Subscriber') - (relationshipA === 'Subscriber');
    if(relationship) return relationship;
    const status = (statusB === 'Active') - (statusA === 'Active');
    if(status) return status;
    const birthday = (new Date(birthDateA)).getTime() - (new Date(birthDateB)).getTime();
    return birthday;
  });

console.log(sorted);

【讨论】：

【解决方案2】：

这是一种方法

let arr = [{status: 'Active', BirthDate: '12/31/1960', Relationship:"Friend"},
{status: 'Active', BirthDate: '12/31/1985', Relationship:"Wife"},
{status: 'Inactive', BirthDate: '12/31/1998', Relationship:"Son"},
{status: 'Inactive', BirthDate: '12/31/1996',Relationship:"Daughter"},
{status: 'Active', BirthDate: '12/31/1995', Relationship:"Daughter"},
{status: 'Active', BirthDate: '12/31/1979', Relationship:"Subscriber"},
{status: 'Inactive', BirthDate: '12/31/1999', Relationship:"Son"}
]

arr.sort((a,b)=> (a.status.localeCompare(b.status) || new Date(a.BirthDate) - new Date(b.BirthDate)));


let index = arr.findIndex(i => i.Relationship === "Subscriber")
arr.unshift(arr.splice(index, 1)[0])

console.log(arr)

【讨论】：