带有外部回调函数代码的突变观察者

Question

我正在尝试重写以下 Mutation Observer 代码：

var target = document.querySelector('div#cart');

var observer = new MutationObserver(function(mutations) {
    mutations.forEach(function(mutation) {
        console.log(mutation.type);
    });
});

var config = { childList: true, attributes: true, characterData: true, subtree: true };
observer.observe(target, config);

进入下面的脚本：

var target = document.querySelector('div#cart'), observer, moCallback, config;

moCallback = function(mutations) {
    mutations.forEach( mutation ) {
        console.log(mutation.type);
    }
};

var array = moCallback;

observer = new MutationObserver( array );

config = { childList: true, attributes: true, characterData: true, subtree: true };
observer.observe(target, config);

第二个脚本对我来说更容易阅读，因为它没有嵌入的回调函数；但是，我无法让它工作。

如何使用外部回调函数而不是内联匿名函数重写我的 Mutation Observer？

Answer 1

这是一个工作示例：

/*
if you run this script on this page, you will see that it works as expected.
*/
var target = document.getElementById('header'); // This is the area you're watching for changes. If it's not working, increase the scope (go up the selector cascade to parent elements).
var observer = new MutationObserver(mutate);

function mutate(mutations) {
    mutations.forEach(function(mutation) { // When the main image changes...
        console.log(mutation.type);
    });
}

var config = { childList: true, attributes: true, characterData: true, subtree: true };
observer.observe(target, config);
setTimeout(function(){
  target.className = "some class";
},2000);