【问题标题】:Run foreach on parsed JSON nested array在解析的 JSON 嵌套数组上运行 foreach
【发布时间】:2021-08-21 22:06:47
【问题描述】:

使用解析的 JSON 文件作为数据输入构建表。 JSON数组中的每个值都应该被分发,同时在运行代码时,JSON数组中的两个值都被注入到同一个元素xml值中。

在我构建“xsl:element”的代码区域中,我可以手动在以下之间进行交换,这一次给我一个数组内容,但我不明白如何让代码迭代数组数据:

<xsl:value-of select="*[1]"/>
<xsl:value-of select="*[2]"/>

JSON:

<data>
{
  "balance-sheets": {
    "sheet-results": {
      "sales": {"values": [3, 5], "title": "Annual sales summary"},
      "costs": {"values": [7, 9], "title": "Accumulated costs per year"}
    }
  }
}
</data>

XSL:

<?xml version="1.0" encoding="UTF-8"?>

<xsl:transform version="3.0"
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  xmlns:ix="http://www.example.org/1"
  xmlns:se="http://www.example.org/2"
  expand-text="yes"
>

  <xsl:output method="xml" indent="yes"/>

  <!-- Block all data that has no user defined template -->
  <xsl:mode on-no-match="shallow-skip"/>

  <xsl:attribute-set name="base">
    <xsl:attribute name="name">se:{parent::*/@key}</xsl:attribute>
  </xsl:attribute-set>

  <!-- Parse JSON file content to XML map -->
  <xsl:template match="data">
    <store>
      <xsl:apply-templates select="json-to-xml(.)/*"/>
    </store>
  </xsl:template>

  <xsl:template match="*[@key='sheet-results']">

    <table>

        <xsl:for-each select="*">

          <tr>

          <td>
            <xsl:value-of select="*[2]"/>
          </td>

          <xsl:for-each select="*">

            <td>
              <span>

                <xsl:element
                  name="ix:nonFraction"
                  use-attribute-sets="base"
                  >
                  <xsl:value-of select="*"/>
                </xsl:element>
              </span>
            </td>

          </xsl:for-each>

      </tr>

        </xsl:for-each>

    </table>

  </xsl:template>

</xsl:transform>

结果:

<?xml version="1.0" encoding="UTF-8"?>
<store xmlns:ix="http://www.example.org/1" xmlns:se="http://www.example.org/2">
   <table>
      <tr>
         <td>Annual sales summary</td>
         <td>
            <span>
               <ix:nonFraction name="se:sales">3 5</ix:nonFraction>
            </span>
         </td>
         <td>
            <span>
               <ix:nonFraction name="se:sales"/>
            </span>
         </td>
      </tr>
      <tr>
         <td>Accumulated costs per year</td>
         <td>
            <span>
               <ix:nonFraction name="se:costs">7 9</ix:nonFraction>
            </span>
         </td>
         <td>
            <span>
               <ix:nonFraction name="se:costs"/>
            </span>
         </td>
      </tr>
   </table>
</store>

想要的结果:

<?xml version="1.0" encoding="UTF-8"?>
<store xmlns:ix="http://www.example.org/1" xmlns:se="http://www.example.org/2">
   <table>
      <tr>
         <td>Annual sales summary</td>
         <td>
            <span>
               <ix:nonFraction name="se:sales">3</ix:nonFraction>
            </span>
         </td>
         <td>
            <span>
               <ix:nonFraction name="se:sales">5</ix:nonFraction>
            </span>
         </td>
      </tr>
      <tr>
         <td>Accumulated costs per year</td>
         <td>
            <span>
               <ix:nonFraction name="se:costs">7</ix:nonFraction>
            </span>
         </td>
         <td>
            <span>
               <ix:nonFraction name="se:costs">9</ix:nonFraction>
            </span>
         </td>
      </tr>
   </table>
</store>

【问题讨论】:

    标签: json xml xslt xslt-3.0


    【解决方案1】:

    考虑以下简化示例:

    XSLT 3.0

    <xsl:stylesheet version="3.0"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:js="http://www.w3.org/2005/xpath-functions"
    exclude-result-prefixes="js">
    <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
    
    <xsl:template match="/">
        <table>
            <xsl:for-each select="json-to-xml(data)/js:map/js:map/js:map/js:map">
                <tr>
                    <th>
                        <xsl:value-of select="js:string[@key='title']"/>
                    </th>
                    <xsl:for-each select="js:array[@key='values']/js:number">
                        <td>
                            <xsl:value-of select="."/>
                        </td>
                    </xsl:for-each>
                </tr>
            </xsl:for-each>
        </table>
    </xsl:template>
    
    </xsl:stylesheet>
    

    应用于您的输入示例,这将返回:

    结果

    <?xml version="1.0" encoding="UTF-8"?>
    <table>
       <tr>
          <th>Annual sales summary</th>
          <td>3</td>
          <td>5</td>
       </tr>
       <tr>
          <th>Accumulated costs per year</th>
          <td>7</td>
          <td>9</td>
       </tr>
    </table>
    

    【讨论】:

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