【发布时间】:2020-11-01 04:11:05
【问题描述】:
错误出现在这一行:Set App...Running Access 2003 并试图在另一个数据库中打开一个表单。我以前做过,但现在似乎不起作用。提前谢谢...
Function OpenDB(DatabasePath As String) As Access.Application
Dim app As Access.Application
Set app = New Access.Application
app.OpenCurrentDatabase DatabasePath
Set OpenDB = app
End Function
【问题讨论】:
标签: vba ms-access database-connection