【发布时间】:2022-01-12 06:59:33
【问题描述】:
使用 for-each-group 我试图通过每个 para 元素的类值添加父节点。我尝试应用分组,但结果不好,我没有得到想要的输出。我对在这种情况下使用分组感到困惑。在这种情况下是否有更好的方法来添加父节点?
当前 XML:
<?xml version="1.0" encoding="utf-8" ?>
<section>
<h1>Some heading</h1>
<section>
<p>normal paragaraph</p>
<p class="list">list 1</p>
<p class="list">list 1</p>
<p>normal paragaraph</p>
<p class="list">list 2</p>
<p class="list">list 2</p>
</section>
<section> ... </section>
</section>
使用的 XSLT:
<xsl:template match="section">
<xsl:for-each-group select="node()" group-by="if (@class='list') then 'list' else 'nolist'">
<xsl:for-each select="current-grouping-key()">
<xsl:choose>
<xsl:when test="current-grouping-key() = 'list'">
<list>
<xsl:apply-templates select="current-group()" />
</list>
</xsl:when>
<xsl:otherwise>
<xsl:apply-templates select="current-group()" />
</xsl:otherwise>
</xsl:choose>
</xsl:for-each>
</xsl:for-each-group>
</xsl:template>
电流输出:
<h1>Some heading</h1>
<p>normal paragaraph</p>
<p>normal paragaraph</p>
<list>
<p class="list">list 1</p>
<p class="list">list 1</p>
<p class="list">list 2</p>
<p class="list">list 2</p>
</list>
<p>normal paragaraph</p>
....
预期输出:
<section>
<h1>Some heading</h1>
<section>
<p>normal paragaraph</p>
<list>
<p class="list">list 1</p>
<p class="list">list 1</p>
</list>
<p>normal paragaraph</p>
<list>
<p class="list">list 2</p>
<p class="list">list 2</p>
</list>
</section>
<section>...</section>
</section>
【问题讨论】:
-
查看现有的
group-adjacent示例xslt-grouping -
:) 是的,这有帮助,谢谢你展示这个。
标签: xslt xslt-2.0 xslt-grouping