使用 XML 填充表答案

【问题标题】：Using XML to populate table使用 XML 填充表
【发布时间】：2022-01-20 02:49:32
【问题描述】：

我正在尝试从 xml 文件中提取数据并将其显示在表格中，但结果并未如我所愿。我希望每个<tag> 都有来自每个<destinationSymbols> 列表的<string> 列表。但就目前而言，它只为每个<destinationSymbols> 返回第一个<string>

<?xml version="1.0"?>
<ArrayOfHighwayRoutingData xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
  <HighwayRoutingData>
    <tag>I80</tag>
    <destinationSymbols>
      <string>SFO</string>
      <string>OAK</string>
      <string>EMR</string>
      <string>ELC</string>
      <string>RIC</string>
      <string>SPB</string>
    </destinationSymbols>
  </HighwayRoutingData>
    <HighwayRoutingData>
    <tag>SR24</tag>
    <destinationSymbols>
      <string>OAK</string>
      <string>ORI</string>
      <string>LFY</string>
      <string>WCR</string>
    </destinationSymbols>
  </HighwayRoutingData>
  <HighwayRoutingData>
    <tag>US101</tag>
    <destinationSymbols>
      <string>SFO</string>
      <string>SSC</string>
      <string>MIL</string>
      <string>PAO</string>
    </destinationSymbols>
  </HighwayRoutingData>

  </ArrayOfHighwayRoutingData>

<?php
$file = "RouteSymbol.xml";
if (file_exists($file)) {
$orders = simplexml_load_file($file,"SimpleXMLElement", LIBXML_NOERROR |  LIBXML_ERR_NONE) or die("Error: Cannot create object");
echo "<table border='1'>";
 foreach ($orders->xpath("//HighwayRoutingData") as $routingPoints){
    $tag=(string)$routingPoints->tag;
    //$string=(string)$routingPoints->string;
     echo "<tr>";
     echo "<td>".$tag."</td>";
 echo "</tr>";
     foreach($orders->xpath("//destinationSymbols") as $symbols){
     $string=(string)$symbols->string;
     echo "<tr>";
     echo "<td>".$string."</td>";
     echo "</tr>";
     /*foreach ($orders->xpath("//destinationSymbols". $tag . """) as $symbol){
    $string=(string)$symbol->string;
    echo "<tr>";
     echo "<td>".$string."</td>";
     //echo "</tr>";*/
}   
}
echo "</table>";
}else{
            echo "Invalid request!";
        }

预期输出

+-------+
| I80   |
+=======+
| SFO   |
+-------+
| OAK   |
+-------+
| EMR   |
+-------+
| ELC   |
+-------+
| RIC   |
+=======+
+-------+
| SR24  |
+=======+
| OAK   |
+-------+
| ORI   |
+-------+
| LFY   |
+-------+
| WCR   |
+=======+
+-------+
| US101 |
+=======+
| SFO   |
+-------+
| SSC   |
+-------+
| MIL   |
+-------+
| PAO   |
+=======+

【问题讨论】：

表达式开头的/ 表示它与文档相关，而不是当前上下文节点。试试.// 而不是//。此外，嵌套循环应该使用在外循环中找到的元素。
您能否编辑问题并显示在给定示例 xml 的情况下您希望表格看起来如何？
@JackFleeting 我添加了预期的输出

标签： php xml

【解决方案1】：

尝试以下方法：

$orders = simplexml_load_string($data);
echo "<table border='1'>";
foreach ($orders->xpath(".//HighwayRoutingData") as $routingPoints){
    $tag=(string)$routingPoints->tag;
     echo "<tr><td><b>{$tag}</b></td>";
     foreach($routingPoints->xpath(".//destinationSymbols//string") as $symbol){
     $x = (string)$symbol;
     echo "<tr><td>{$x}</td></tr>";
} 
      echo "</tr>";
}
echo "</table>";

输出应该是您的预期输出。

【讨论】：