在 Base64 ActionScript 3.0 中解码 XML

Question

我正在尝试导入在 Flash 中经过 Base64 编码的 XML 文件。导入相当简单：

var myXML:XML;
var myLoader:URLLoader = new URLLoader();
myLoader.load(new URLRequest("encoded.xml"));
myLoader.addEventListener(Event.COMPLETE, processXML);

function processXML(e:Event):void
{
    myXML = new XML(e.target.data);
    trace(myXML);
}

现在我想知道如何解码它。我找到了一个我认为可以工作的类，但我不确定一旦导入它后如何将它应用到 XML 中。我的问题是我将如何使用下面的类来解码 XML，或者还有其他方法可以解决吗？

package com.base64 { 
    /**
    * Encodes and decodes a base64 string.
    * @authors Sven Dens - http://www.svendens.be
    * @version 0.1
    *
    * Original Javascript implementation:
    * Aardwulf Systems, www.aardwulf.com
    * See: http://www.aardwulf.com/tutor/base64/base64.html
    */
    import flash.system.System;

    public class Base64 {
        /**
        * Variables
        * @exclude
        */
        protected static var base64chars:String = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/=";

        /**
        * Encodes a base64 string.
        */
        public static function encode(src:String):String {
            var i:Number = 0;
            var output:String = new String("");
            var chr1:Number, chr2:Number, chr3:Number;
            var enc1:Number, enc2:Number, enc3:Number, enc4:Number;
            while (i < src.length) {
                chr1 = src.charCodeAt(i++);
                chr2 = src.charCodeAt(i++);
                chr3 = src.charCodeAt(i++);
                enc1 = chr1 >> 2;
                enc2 = ((chr1 & 3) << 4) | (chr2 >> 4);
                enc3 = ((chr2 & 15) << 2) | (chr3 >> 6);
                enc4 = chr3 & 63;
                if(isNaN(chr2)) enc3 = enc4 = 64;
                else if(isNaN(chr3)) enc4 = 64;
                output += base64chars.charAt(enc1)+base64chars.charAt(enc2);
                output += base64chars.charAt(enc3)+base64chars.charAt(enc4)
            }
            return output;
        }

        /**
        * Decodes a base64 string.
        */
        public static function decode(src:String):String {
            var i:Number = 0;
            var output:String = new String("");
            var chr1:Number, chr2:Number, chr3:Number;
            var enc1:Number, enc2:Number, enc3:Number, enc4:Number;
            while (i < src.length) {
                enc1 = base64chars.indexOf(src.charAt(i++));
                enc2 = base64chars.indexOf(src.charAt(i++));
                enc3 = base64chars.indexOf(src.charAt(i++));
                enc4 = base64chars.indexOf(src.charAt(i++));
                chr1 = (enc1 << 2) | (enc2 >> 4);
                chr2 = ((enc2 & 15) << 4) | (enc3 >> 2);
                chr3 = ((enc3 & 3) << 6) | enc4;
                output += String.fromCharCode(chr1);
                if (enc3 != 64) output = output+String.fromCharCode(chr2);
                if (enc4 != 64) output = output+String.fromCharCode(chr3);
            }
            return output;
        }

    }
}

Answer 1

嗯，使用你的类，应该很简单

myXML = XML(Base64.decode(e.target.data));

如果不行，检查解码器的返回值：

trace(Base64.decode(e.target.data));