box2d，如何检测静态和动态物体之间的碰撞答案

【问题标题】：box2d, how to detect collision between static and dynamic bodiesbox2d，如何检测静态和动态物体之间的碰撞
【发布时间】：2011-08-04 05:36:30
【问题描述】：

我正在聆听动态物体之间的接触。但不能听动静体之间的接触。

我可以使用这个方法在我的 b2contactListener 类上处理碰撞检测。

    public override function BeginContact(contact:b2Contact):void {
        // getting the fixtures that collided
        var fixtureA:b2Fixture=contact.GetFixtureA();
        var fixtureB:b2Fixture=contact.GetFixtureB();
        // if the fixture is a sensor, mark the parent body to be removed

        if(fixtureB.GetBody().getUniqueBodyName() == "towerBody"){
            //Towerbody is static body
                    trace("BINGOOOOOO");
                    }  

        if (fixtureA.GetBody().getUniqueBodyName() == "bomb"){
            // Bomb is dynamic body
        //  main.gamePhysics.destroyBodyWhenCollide(fixtureA.GetBody());

            var spr:Sprite = fixtureA.GetBody().GetUserData();
            spr.alpha = 0;
            fixtureA.GetBody().collisionDetected = true;            

        }

请帮帮我...

【问题讨论】：

标签： flash actionscript box2d flash-builder

【解决方案1】：

静态主体将是fixtureB 的假设不正确......它可能是fixtureA。

尝试测试一下...

public override function BeginContact(contact:b2Contact):void {
    // getting the fixtures that collided
    var fixtureA:b2Fixture=contact.GetFixtureA();
    var fixtureB:b2Fixture=contact.GetFixtureB();
    // if the fixture is a sensor, mark the parent body to be removed

    if(fixtureA.GetBody().getUniqueBodyName() == "towerBody"){
        //Towerbody is static body
                trace("BINGOOOOOO - A");
                }  

    if(fixtureB.GetBody().getUniqueBodyName() == "towerBody"){
        //Towerbody is static body
                trace("BINGOOOOOO - B");
                }  


    if (fixtureA.GetBody().getUniqueBodyName() == "bomb"){
        // Bomb is dynamic body
    //  main.gamePhysics.destroyBodyWhenCollide(fixtureA.GetBody());

        var spr:Sprite = fixtureA.GetBody().GetUserData();
        spr.alpha = 0;
        fixtureA.GetBody().collisionDetected = true;            

    }

【讨论】：