【发布时间】:2019-03-29 03:25:00
【问题描述】:
借用question 中的示例数据,如果我有以下数据并且我拟合了以下非线性模型,我该如何计算 95% 预测 间隔 适合我的曲线?
library(broom)
library(tidyverse)
x <- seq(0, 4, 0.1)
y1 <- (x * 2 / (0.2 + x))
y <- y1 + rnorm(length(y1), 0, 0.2)
d <- data.frame(x, y)
mymodel <- nls(y ~ v * x / (k + x),
start = list(v = 1.9, k = 0.19),
data = d)
mymodel_aug <- augment(mymodel)
ggplot(mymodel_aug, aes(x, y)) +
geom_point() +
geom_line(aes(y = .fitted), color = "red") +
theme_minimal()
例如,我可以很容易地从线性模型中计算预测区间,如下所示:
## linear example
d2 <- d %>%
filter(x > 1)
mylinear <- lm(y ~ x, data = d2)
mypredictions <-
predict(mylinear, interval = "prediction", level = 0.95) %>%
as_tibble()
d3 <- bind_cols(d2, mypredictions)
ggplot(d3, aes(x, y)) +
geom_point() +
geom_line(aes(y = fit)) +
geom_ribbon(aes(ymin = lwr, ymax = upr), alpha = .15) +
theme_minimal()
【问题讨论】:
标签: r predict nls non-linear-regression