访问查询按天汇总并按小时/分钟计数

Question

我正在尝试使用以下数据编写查询。我的挑战是每天，我需要计算“105”出现在 Col A 和“100”出现在 Col B 的次数。我不需要计算每个实例“105”出现，而是每分钟出现“105”出现。 Col B 和 "100" 也是如此

Date           Time      A   B
1/20/2021   1:06:12 AM  105 100
1/20/2021   1:06:16 AM  105 100
1/20/2021   1:06:20 AM  105 100
1/20/2021   2:28:12 AM  105 100
1/20/2021   2:28:16 AM  105 100
1/20/2021   2:28:20 AM  105 100
1/20/2021   3:50:08 AM  105 10
1/20/2021   3:50:12 AM  105 10
1/20/2021   3:50:16 AM  105 10
1/20/2021   5:12:04 AM  105 10
1/20/2021   5:12:08 AM  105 10
1/20/2021   5:12:12 AM  105 10

详情：

Time  A  B
1:06  1  1
2:28  1  1
3:50  1  0
5:12  1  0

查询结果：

Date      A    B
1/21/20   4    2

任何有关如何执行此操作的建议将不胜感激。

Answer 1

一种方法是在每一列上分别使用distinct。然后聚合：

select date, sum(a), sum(b)
from (select distinct date, hour(time) as hh, minute(time) as mm, 1 as a, 0 as b
      from t
      where a = 105
      union all
      select distinct date, hour(time) as hh, minute(time) as mm, 0 as a, 1 as b
      from t
      where b = 100
     ) t
group by date;