【发布时间】:2011-08-20 07:31:52
【问题描述】:
我在下面有 2 张桌子:
Table_1
[Group No] [Test No] [Description]
123 1 [First Test]
123 2 [Second Test]
123 3 [Third Test]
Table_2
[Sample No] [Test No] [Result Description]
ABC 1 [Some More Result]
ABC 3 [Some Result]
DEF 1 [A Result]
DEF 2 [Results More]
DEF 3 [Bad Results]
这是我的查询:
SELECT Table_1.[Group No], Table_1.[Test No], Table_1.Description, Table_2.[Result Description]
FROM Table_1
LEFT OUTER JOIN Table_2 ON Table_1.[Test No] = Table_2.[Test No]
WHERE (Table_1.[Group No] = '123') AND (Table_2.[Sample No] = 'ABC')
djacobson 的询问:
SELECT Table_1.[Group No], Table_1.[Test No], Table_1.Description, Table_2.[Result Description]
FROM Table_1
LEFT OUTER JOIN Table_2 ON Table_1.[Test No] = Table_2.[Test No]
WHERE (Table_1.[Group No] = '123')
AND (Table_2.[Sample No] IS NULL OR Table_2.[Sample No] = 'ABC')
这会返回:
[Group No] [Test No] [Description] [Result Description]
123 1 [First Test] [Some More Result]
123 3 [Third Test] [Some Result]
但我真正想要的是:
[Group No] [Test No] [Description] [Result Description]
123 1 [First Test] [Some More Result]
123 2 [Second Test] NULL
123 3 [Third Test] [Some Result]
这可能吗?我想返回Test No 2的记录。但是,我如何加入一个不存在的记录?或者这根本不可能?有哪些替代方案?
【问题讨论】:
标签: sql-server left-join