尝试根据一列的值进行两次 MySQL 计算 [关闭]

Question

我有一个 select 语句，但想要评估一列，如果它包含 584 的值。我正在尝试通过将其他 3 列相乘来创建一个名为 total 的新计算列，如果不是 584，则根据不同的列进行计算

    select CASE `d2c_3_csg_batch_in`.`transactioncode` AS `transactioncode`,
`d2c_3_csg_batch_in`.`site` AS `site`,
`d2c_3_csg_employees`.`lastname` AS `lastname`,
`d2c_3_csg_employees`.`firstname` AS `firstname`,
`d2c_3_csg_employees`.`payrate` AS `payrate`,
`d2c_3_csg_batch_in`.`employeecode` AS `employeecode`,
`d2c_3_csg_batch_in`.`jobcode` AS `jobcode`,
`d2c_3_csg_employees`.`CompanyFrequency` AS `CompanyFrequency`,
`d2c_3_csg_batch_in`.`inputunits` AS `inputunits`,
`d2c_3_csg_transactioncodes`.`multiplier` AS `multiplier`,
`d2c_3_csg_transactioncodes`.`payspacewording` AS `payspacewording`,
        WHEN `d2c_3_csg_batch_in`.`transactioncode` = '584' THEN `d2c_3_csg_batch_in`.`inputunits` AS `total`
        WHEN `d2c_3_csg_batch_in`.`transactioncode` <> '584' THEN `d2c_3_csg_batch_in`.`inputunits` * `d2c_3_csg_employees`.`payrate` * `d2c_3_csg_transactioncodes`.`multiplier` AS `total` 
     END
from ((`d2c_3_csg_transactioncodes` join `d2c_3_csg_batch_in` on(`d2c_3_csg_transactioncodes`.`code` = `d2c_3_csg_batch_in`.`transactioncode`)) 
left join `d2c_3_csg_employees` on(`d2c_3_csg_batch_in`.`employeecode` = `d2c_3_csg_employees`.`employeenumber`)) 
where `d2c_3_csg_batch_in`.`flag` = 'ADD' and `d2c_3_csg_batch_in`.`prp` = 'Y' 
group by `d2c_3_csg_batch_in`.`employeecode`,`d2c_3_csg_batch_in`.`transactioncode` 
order by `d2c_3_csg_batch_in`.`employeecode` desc,`d2c_3_csg_batch_in`.`transactioncode`

Answer 1

尝试使用 Sum if 例如

SUM(if (q1.bill = 584,q1.bill - q1.payment,0))AS bal,
SUM(if (q1.bill != 584,q1.payment - q1.bill  ,0))AS advpay,

q1 是表别名。其他领域是虚构的

纠正点：用case的时候，你这样做；

CASE WHEN `d2c_3_csg_batch_in`.`transactioncode` = '584' 
         THEN `d2c_3_csg_batch_in`.`inputunits` 
     WHEN `d2c_3_csg_batch_in`.`transactioncode` <> '584' 
         THEN `d2c_3_csg_batch_in`.`inputunits` * `d2c_3_csg_employees`.`payrate` * `d2c_3_csg_transactioncodes`.`multiplier` 
END AS `total`    -- an alias must be there!