【发布时间】:2022-01-19 06:25:52
【问题描述】:
我写的代码是:
t = table(1:0, `Id`Factor`DataSource`Parameter, [INT, STRING, STRING, DOUBLE[]]);
insert into t values(0, "f1", "tt", [[100, 14, 14]]);
Date = 2021.01.02 2021.01.02 2021.01.04 2021.01.05 2021.01.07 2021.01.08
X = 1 4 10 -1 2 4
tt = table(Date,X as x)
def f1(tt, params){
a = select Date, mstd(x,params[0]), mstd(x,params[1]), mstd(x,params[2]) from tt ;
return a
}
def f(func_name, table_name, params){
return funcByName(func_name)(objByName(table_name), params);
}
each(f, t.Factor, t.DataSource, t.Parameter)
但是报错:
each(f, t."Factor", t."DataSource", t."Parameter") => f: return funcByName(func_name) (objByName(table_name), params) => f1: a = 选择 Date,mstd(x, params[0]) as mstd_x from tt => 用法:mstd(X, 窗口,[minPeriods])。窗口必须至少为 2。
我在列中使用 arrayvector 来创建表,不确定是否是问题所在。我该如何解决?
【问题讨论】:
标签: dolphindb