【发布时间】:2015-04-11 04:14:11
【问题描述】:
我正在使用在 Internet 上找到的 Huffman 代码来获取以矩阵形式存储在 2D 数组中的随机整数的频率。
霍夫曼代码链接 - Java:http://rosettacode.org/wiki/Huffman_coding
方法 Q1 要求用户设置矩阵大小。矩阵用随机整数 [0, 255] 填充。
public void q1(){
System.out.println();
System.out.println("Question 1 - Creating Random Matrix");
Scanner in = new Scanner(System.in);
//Matrix number of rows
System.out.print("Insert size of rows M: ");
rows = in.nextInt();
//Matrix number of columns
System.out.print("Insert size of columns N: ");
columns = in.nextInt();
System.out.println();
matrix = new int[rows][columns];
//Initialising randomisation
Random r = new Random();
//Filling matrix and printing values
for (int m = 0; m < rows; m++){
for (int n = 0; n < columns; n++){
matrix[m][n] = r.nextInt(256);
System.out.print("[" + matrix[m][n] + "] \t");
}
System.out.print("\n");
}
System.out.println();
}
方法Q2需要重新显示矩阵中找到的所有随机整数及其频率。
public void q2() {
// we will assume that all our characters will have code less than 256, for simplicity
int[] charFreqs = new int[256];
StringBuilder sb = new StringBuilder();
String [] st = new String[5];
System.out.println();
System.out.println("Alphabet " + "\t" + "Frequency" + "\t" + "Probability");
for (int m = 0; m < rows; m++){
for (int n = 0; n < columns; n++){
String sentence = String.valueOf(matrix[m][n]);
System.out.print(matrix[m][n] + "\n");
//read each character and record the frequencies
for (int i = 0; i < sentence.length(); i++){
char c = sb.append(sentence[i]);
}
for (char c : sentence.toCharArray()){
charFreqs[c]++;
}
}
}
// build tree
HuffmanTree tree = buildTree(charFreqs);
// print out results
System.out.println("SYMBOL\tWEIGHT\tHUFFMAN CODE");
printCodes(tree, new StringBuffer());
}
当前程序通过将随机整数拆分为单独的数字来计算频率。我需要根据每个随机整数计算频率。
有什么帮助吗?
谢谢
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标签: java symbols huffman-code frequency-distribution