Swashbuckle SwaggerResponseRemoveDefaults 属性仍然向 Swagger 添加 200 Success 响应

Question

我在 .NET Core 3.1 项目中使用 Swashbuckle 和 Swagger UI，并将我的 XML cmets 导入 Swagger。我在控制器上有一个 POST 请求，我想在 Swagger 中注册多个响应状态（201、401、403、404）。问题是我还在 swagger.json 文件和 Swagger UI 界面中看到与我明确指定的状态代码响应一起列出的 200 Success 响应。

正如在多个不同的地方所建议的那样，我正在使用 [SwaggerResponseRemoveDefaults] 属性来尝试防止这种情况发生，但是我尝试的所有操作仍然会导致列出默认的 200 响应。

我试过了：

• 将属性添加到方法中，
• 将属性添加到控制器，
• 将属性添加到抽象基控制器，

以及以上所有组合。我也尝试过结合这些：

• 使用 XML <response code="XXX"></response> 注释标签指定所需的响应类型，以及
• 使用[SwaggerResponse(XXX)] 端点指定所需的响应类型。

没有任何结果导致从我的 Swagger UI 和 swagger.json 中删除 200 Success 结果。

TrackerController.cs

/// <summary>...</summary>
/// <response code="401">User is not authenticated.</response>
/// <response code="404">Tracker not found.</response>
[Authorize]
[ApiController]
[Route("[controller]")]
[SwaggerResponseRemoveDefaults]
public partial class TrackersController : AbstractController
{
    ...

    /// <summary>...</summary>
    /// <param name="tracker">The details of the tracker to be created.</param>
    /// <response code="201">The tracker was successfully created.</response>
    /// <response code="403">User is not authorized to modify this resource.</response>
    [HttpPost]
    [SwaggerResponseRemoveDefaults]
    [ResponseType(typeof(TrackerDto))]
    [SwaggerResponse(201, Description = "The tracker was successfully created.")]
    public async Task<IActionResult> CreateTracker([FromBody] TrackerDto tracker)
    {
        ...
    }

    ...

}

swagger.json

{
  "openapi": "3.0.1",
  "info": {
    "title": "My API",
    "version": "v1"
  },
  "paths": {
    "/Trackers": {
      "post": {
        "tags": [
          "Trackers"
        ],
        "summary": "Create a new tracker.",
        "requestBody": {
          "description": "The details of the tracker to be created.",
          "content": {
            "application/json-patch+json": {
              "schema": {
                "$ref": "#/components/schemas/TrackerDto"
              }
            },
            "application/json": {
              "schema": {
                "$ref": "#/components/schemas/TrackerDto"
              }
            },
            "text/json": {
              "schema": {
                "$ref": "#/components/schemas/TrackerDto"
              }
            },
            "application/*+json": {
              "schema": {
                "$ref": "#/components/schemas/TrackerDto"
              }
            }
          }
        },
        "responses": {
          "200": {
            "description": "Success"
          },
          "201": {
            "description": "The tracker was successfully created."
          },
          "401": {
            "description": "User is not authenticated."
          },
          "403": {
            "description": "User is not authorized to modify this resource."
          },
          "404": {
            "description": "Tracker not found."
          }
        }
      }
    }
  }
}

Swagger UI Screenshot

Answer 1

现在，您告诉 Swagger 您正在生成一个默认类型为 200 的TrackerDto，此外另一个响应为 201。您需要将其 设为一个 em> 匹配对。

删除ResponseType 属性并将类型放在它所属的位置：

[SwaggerResponse(201, Description = "The tracker was successfully created.", typeof(TrackerDto))]

你也可以试试：

[ProducesResponseType(typeof(TrackerDto), 201)]

重要的是将类型和状态码放在同一个属性中，这样 Swagger 就知道它们属于同一类。