XmlSerializer 序列化子对象

Question

下面的怎么序列化

[XmlRoot("response")]
public class MyCollection<T>
{
    [XmlElement("person", Type = typeof(Person))]
    public List<T> entry;
    public int startIndex;
}

其中 T 可以是类，如

public class Person
{
    public string name;
}

进入

<response>
  <startIndex>1</startIndex>
  <entry>
      <person>
         <name>meeee</name>
      </person>
  </entry>
  <entry>
      <person>
         <name>youuu</name>
      </person>
  </entry>
</response>

我一直在玩 [XmlArray]、[XmlArrayItem] 和 [XmlElement]，但我似乎无法获得正确的组合。啊啊啊。

更新：

[XmlArray("entry")]
[XmlArrayItem("person", Type = typeof(Person))]
public List<T> entry;

给我

<entry><person></person><person></person></entry>


[XmlElement("person", Type = typeof(Person))]
public List<T> entry;

给我

<person></person><person></person>

Answer 1

我找到了一种不使用 IXmlSerializable 的方法。使用 XmlDictionaryWriter 格式化必要的部分，其余部分只需使用 DataContractSerializer。我为 MyCollection 创建了一个接口

public interface IMyCollection
{
    int getStartIndex();
    IList getEntry();
}

因此，MyCollection 不再使用任何 XMLxxxx 属性进行修饰。转换为字符串的方法如下。可以改进吗？

public string ConvertToXML(object obj)
{
    MemoryStream ms = new MemoryStream();
    using (XmlDictionaryWriter writer = XmlDictionaryWriter.CreateTextWriter(ms, Encoding.UTF8, true))
    {
         writer.WriteStartDocument();
         if (obj is IMyCollection)
         {
              IMyCollection collection = (IMyCollection)obj;
              writer.WriteStartElement("response");
              writer.WriteElementString("startIndex","0");
              var responses = collection.getEntry();
              foreach (var item in responses)
              {
                   writer.WriteStartElement("entry");
                   DataContractSerializer ser = new DataContractSerializer(item.GetType());                
                   ser.WriteObject(writer, item);
                   writer.WriteEndElement();
              }
              writer.WriteEndElement();
        }
        writer.Flush();
        return Encoding.UTF8.GetString(ms.ToArray());
}

Answer 2

这听起来像我遇到的类似问题..我终于破解了它并将所有内容发布在问题here..

XML Serialization and Inherited Types

这样有用吗？

Answer 3

在不彻底改变类的情况下，我看不到任何明显的方法可以让它输出这些结果......这可能不是你想要的，但通过镜像所需的输出（在 DTO 中并不罕见）它得到了正确的结果...

否则，您可能正在查看IXmlSerializable，这是一个巨大的痛苦：

using System;
using System.Collections.Generic;
using System.Xml.Serialization;
[XmlRoot("response")]
public class MyResponse {
    public MyResponse() {
        Entries = new List<Entry>();
    }
    [XmlElement("startIndex", Order = 1)]
    public int StartIndex { get; set; }
    [XmlElement("entry", Order = 2)]
    public List<Entry> Entries { get; set; }
}
public class Entry {
    public Entry() { }
    public Entry(Person person) { Person = person; }
    [XmlElement("person")]
    public Person Person { get; set; }
    public static implicit operator Entry(Person person) {
        return person == null ? null : new Entry(person);
    }
    public static implicit operator Person(Entry entry) {
        return entry == null ? null : entry.Person;
    }
}
public class Person {
    [XmlElement("name")]
    public string Name { get; set; }
}
static class Program {
    static void Main() {
        MyResponse resp = new MyResponse();
        resp.StartIndex = 1;
        resp.Entries.Add(new Person { Name = "meeee" });
        resp.Entries.Add(new Person { Name = "youuu" });
        XmlSerializer ser = new XmlSerializer(resp.GetType());
        ser.Serialize(Console.Out, resp);
    }
}