【发布时间】:2016-12-02 00:08:32
【问题描述】:
我是 XSLT 的新手,这个示例看起来是一种很好的学习方式,但我一生都无法让它发挥作用。我正在尝试并行标记 2 个不同的字符串并将它们组合成一个 JSON 数组。所以我想标记 measTypes[0] 并匹配到 measResults[0],然后是 measTypes[1] 并匹配到 measResults[1],依此类推
示例 XML
<?xml version="1.0" encoding="UTF-8"?>
<measInfo measInfoId="1542455297">
<measTypes>1542455297 1542455298 1542455299 1542455300 1542455301 1542455302 1542455303 1542455304 1542455305 1542455306 1542455307 1542460296 1542460297 </measTypes>
<measValue measObjLdn="LTHAB0113422/ETHPORT:Cabinet No.=0, Subrack No.=1, Slot No.=7, Port No.=0, Subboard Type=BASE_BOARD">
<measResults>116967973 585560 496041572 682500 0 12583680 72080 520454 46670568 73432 2205837 1000000 1000000 </measResults>
</measValue>
<measValue measObjLdn="LTHAB0113422/ETHPORT:Cabinet No.=0, Subrack No.=1, Slot No.=7, Port No.=1, Subboard Type=BASE_BOARD">
<measResults>0 0 0 0 0 0 0 0 0 0 0 0 0 </measResults>
</measValue>
</measInfo>
我目前拥有的 XSLT 2.0
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform” xmlns:xs="http://www.w3.org/2001/XMLSchema” exclude-result-prefixes=“xs" version="2.0">
<xsl:output method="text" encoding="UTF-8" media-type="text/plain"/>
<xsl:strip-space elements="*"/>
<!--
<xsl:template match="/measInfo/measValue/measResults" name="measRes">
<xsl:for-each select=".">
{'measResult':{<xsl:value-of select="tokenize(normalize-space(.),'\s+')"/>}
</xsl:for-each>
</xsl:template>
-->
<xsl:template match="/" name="measObj">
[
<xsl:for-each select="measInfo/measValue">
'measObjLdn':'<xsl:value-of select="@measObjLdn"/>'
<xsl:call-template name="types"/>
</xsl:for-each>
]
<xsl:apply-templates />
</xsl:template>
<xsl:template match="/measInfo" name="types" >
'Metrics':[
<xsl:for-each select="tokenize(normalize-space(measTypes),'\s+')">
{'measType':'<xsl:value-of select="."/>'},<!-- <xsl:call-template name="measRes"/> -->
</xsl:for-each>
]
</xsl:template>
</xsl:stylesheet>
我希望的 JSON 结果
[
'measObjLdn':"LTHAB0113422/ETHPORT:Cabinet No.=0, Subrack No.=1, Slot No.=7, Port No.=0, Subboard Type=BASE_BOARD",
'Metrics':[
{'measType':'1542455297','measResult':116967973},
{'measType':'1542455298','measResult':585560},
{'measType':'1542455299','measResult':496041572},
{'measType':'1542455300','measResult':682500},
{'measType':'1542455301','measResult':0},
{'measType':'1542455302','measResult':12583680},
{'measType':'1542455303','measResult':72080},
{'measType':'1542455304','measResult':520454},
{'measType':'1542455305','measResult':46670568},
{'measType':'1542455306','measResult':73432},
{'measType':'1542455307','measResult':2205837},
{'measType':'1542460296','measResult':1000000},
{'measType':'1542460297','measResult':1000000}
]
'measObjLdn':"LTHAB0113422/ETHPORT:Cabinet No.=0, Subrack No.=1, Slot No.=7, Port No.=1, Subboard Type=BASE_BOARD",
'Metrics':[
{'measType':'1542455297','measResult':0},
{'measType':'1542455298','measResult':0},
{'measType':'1542455299','measResult':0},
{'measType':'1542455300','measResult':0},
{'measType':'1542455301','measResult':0},
{'measType':'1542455302','measResult':0},
{'measType':'1542455303','measResult':0},
{'measType':'1542455304','measResult':0},
{'measType':'1542455305','measResult':0},
{'measType':'1542455306','measResult':0},
{'measType':'1542455307','measResult':0},
{'measType':'1542460296','measResult':0},
{'measType':'1542460297','measResult':0}
]
]
【问题讨论】:
-
'measObjLdn':{LTHAB0113422/ETHPORT:Cabinet No.=0在我看来不像 JSON。 -
对不起,太多的剪切和粘贴所有的代码sn-ps。现在应该是正确的
-
您需要编写一个模板或函数,以两个序列作为参数,然后为每个序列中的第一项对构建 JSON 对象字面量,并在尾部分别调用模板函数序列。 XPath 3.0 有
for-each-pair可以做到这一点,但当然您可以在自己的函数中实现它。 w3.org/TR/xpath-functions-31/#func-for-each-pair
标签: json xml-parsing xslt-2.0