【问题标题】:Spring 3 REST with XML gives "406 Not Acceptable"带有 XML 的 Spring 3 REST 给出“406 Not Acceptable”
【发布时间】:2011-08-30 22:39:21
【问题描述】:

我正在尝试使用 Spring 3 实现 REST Remoting,但我无法通过“406 Not Acceptable”错误... 我尝试远程返回应用程序/xml 内容的 1 个服务。每次我使用“Accept=application/xml”发送请求时,都会收到 406 错误。每次我用一些不同的“Accept”标头发送它时,我都会得到 404(和 handleNoSuchRequestHandlingMethod 异常)。正如我在日志中看到的那样,服务本身被调用。我还发现,在 servlet 初始化期间,我收到以下错误,尽管我不确定这是否是一个问题:

没有找到要委托给的任何 ViewResolver;请使用 ContentNegotiatingViewResolver 上的“viewResolvers”属性配置它们

我尝试了许多不同的配置,但都没有成功。也许您可以在我的实现中发现一些错误?

extService-servlet.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:util="http://www.springframework.org/schema/util"
    xmlns:aop="http://www.springframework.org/schema/aop" xmlns:context="http://www.springframework.org/schema/context"
    xmlns:task="http://www.springframework.org/schema/task" xmlns:mvc="http://www.springframework.org/schema/mvc"
    xmlns:oxm="http://www.springframework.org/schema/oxm" xmlns:p="http://www.springframework.org/schema/p"
    xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
                        http://www.springframework.org/schema/util http://www.springframework.org/schema/util/spring-util-3.0.xsd
                        http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-3.0.xsd
                        http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd
                        http://www.springframework.org/schema/task http://www.springframework.org/schema/task/spring-task-3.0.xsd
                        http://www.springframework.org/schema/oxm http://www.springframework.org/schema/oxm/spring-oxm-3.0.xsd
                        http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd">

    <context:component-scan base-package="ch.epimmo.immogreen.backend.mvc" />

    <mvc:annotation-driven />

    <oxm:jaxb2-marshaller id="jaxbMarshaller">
        <oxm:class-to-be-bound name="ch.epimmo.immogreen.common.dto.ExpertDto" />
    </oxm:jaxb2-marshaller>


    <bean
        class="org.springframework.web.servlet.view.ContentNegotiatingViewResolver"
        p:order="#{T(org.springframework.core.Ordered).HIGHEST_PRECEDENCE}">
        <property name="defaultContentType" value="text/html" />
        <!-- <property name="ignoreAcceptHeader" value="true" /> -->
        <property name="favorPathExtension" value="true" />
        <property name="mediaTypes">
            <map>
                <entry key="xml" value="application/xml" />
            </map>
        </property>
        <property name="defaultViews">
            <list>
                <bean class="org.springframework.web.servlet.view.xml.MarshallingView">
                    <property name="marshaller" ref="jaxbMarshaller" />
                </bean>
            </list>
        </property>
    </bean>
</beans>

控制器

@Controller
@RequestMapping( { "extService" })
public class ExtServiceController {

    protected final static Logger LOGGER = Logger.getLogger(ExtServiceController.class);

    @Autowired
    private UserManagementService userManagementService;    

    // @RequestMapping(value = "/experts", method = RequestMethod.GET, headers = { "Accept=*/*" })
    // @RequestMapping(value = "experts", method = RequestMethod.GET)
    @RequestMapping(value = "experts", method = RequestMethod.GET, headers = { "Accept=application/xml, text/xml" })
    public @ResponseBody
    ExpertDto getExperts() {            
              return new ExpertDto();
    }
}

测试

DefaultHttpClient httpClient = new DefaultHttpClient();

String expertsUrl = "http://localhost:8080/extService/experts";

HttpGet getRequest = new HttpGet(expertsUrl);
getRequest.setHeader(new BasicHeader("Accept", "application/xml"));
// getRequest.setHeader(new BasicHeader("Accept", "text/html"));
// getRequest.setHeader(new BasicHeader("Accept", "*/*"));

HttpResponse response = httpClient.execute(getRequest);
HttpEntity entity = response.getEntity();
InputStream content = entity.getContent();

【问题讨论】:

    标签: xml model-view-controller spring rest http-status-code-406


    【解决方案1】:

    考虑使用以下方法而不是@ResponseBody

    @RequestMapping(value = "experts", method = RequestMethod.GET)
    public @ResponseBody
    void getExperts(org.springframework.ui.Model model) {            
          model.addAttribute(new ExpertDto());
    }
    

    “没有找到要委托给...的任何 ViewResolvers”只是一个警告,您可以忽略它。

    【讨论】:

      【解决方案2】:

      将你的@RequestMapping 注解修改为

      @RequestMapping(value = "experts", method = RequestMethod.GET, headers = { "Accept=application/xml" })

      【讨论】:

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