【发布时间】:2011-06-08 00:08:25
【问题描述】:
我正在使用 Oracle SQL Developer 编写代码。我有一个简单的选择语句有效:
SELECT
CFS.CAE_SEC_ID,
CFS.FM_SEC_CODE,
CFS.LAST_USER_ID,
case
when 1 = 1 then
sl.usbank_to_edit
else
case
when 'ENT\CB174' = CFS.last_user_id then
sl.owner_to_edit
else
sl.to_edit
end
end canEdit
FROM
CAEDBO.CAE_FOF_SECURITY CFS
INNER JOIN caedbo.CAE_DATA_SET_ELEMENT CDSE_STAT
ON (CDSE_STAT.DATA_SET_ELEMENT_ID = CFS.APPR_STATUS)
INNER JOIN caedbo.CAE_STATE_LOOKUP sl
ON (sl.object_state = CDSE_STAT.data_set_element_id)
where
cfs.CAE_SEC_ID in (3741, 3744, 3748, 3752);
但是我想向它添加一些变量并引用语句中的变量,类似于下面,并在代码窗口中运行它。我该如何正确地做到这一点?
DECLARE
p_USBank_n NUMBER;
p_user_id_c VARCHAR2(20);
BEGIN
p_USBank_n := 1;
p_user_id_c := 'ENT\CB174';
SELECT
CFS.CAE_SEC_ID,
CFS.FM_SEC_CODE,
CFS.LAST_USER_ID,
case
when p_USBank_n = 1 then
sl.usbank_to_edit
else
case
when p_user_id_c = CFS.last_user_id then
sl.owner_to_edit
else
sl.to_edit
end
end canEdit
FROM
CAEDBO.CAE_FOF_SECURITY CFS
INNER JOIN caedbo.CAE_DATA_SET_ELEMENT CDSE_STAT
ON (CDSE_STAT.DATA_SET_ELEMENT_ID = CFS.APPR_STATUS)
INNER JOIN caedbo.CAE_STATE_LOOKUP sl
ON (sl.object_state = CDSE_STAT.data_set_element_id)
where
cfs.CAE_SEC_ID in (3741, 3744, 3748, 3752);
END;
当我在 sql 窗口中运行时,我收到以下消息:
Error report:
ORA-06550: line 8, column 5:
PLS-00428: an INTO clause is expected in this SELECT statement
06550. 00000 - "line %s, column %s:\n%s"
*Cause: Usually a PL/SQL compilation error.
*Action:
【问题讨论】:
-
呃,如果我能弄清楚,那我就不会问我会不会..那是什么愚蠢的评论?如果你没有什么建设性的话请不要说什么,谢谢
标签: oracle plsql oracle-sqldeveloper