Laravel - 聚合函数中的语法错误或访问冲突

Question

我想执行聚合函数并达到下图所示的结果：

新结果：

我有这个问题：

        $subscribers= Cloudsubscriptions::join("services","cloudsubscriptions.service_name","=","services.name")
            ->join("service_type","services.service_type","=","service_type.id")
            ->select("cloudsubscriptions.service_name"
                    ,"service_type.name as service_type"
                    ,DB::raw("(SELECT count(cloudsubscriptions.id) FROM 'cloudsubscriptions' WHERE 'is_subscribe' = 1) as total_active_users")
                    ,DB::raw("(SELECT count(cloudsubscriptions.id) FROM 'cloudsubscriptions' WHERE 'is_subscribe' = 0) as total_inactive_users")
                    ,DB::raw("(SELECT count(cloudsubscriptions.id) FROM 'cloudsubscriptions') as total_users"))
            ->groupBy("cloudsubscriptions.service_name")
        ->get();

我希望在图表中显示结果，但出现此错误

"SQLSTATE[42000]: 语法错误或访问冲突：1064 您的 SQL 语法有错误；请查看与您的 MariaDB 服务器版本相对应的手册，了解在 ''cloudsubscriptions' WHERE 'is_subscribe' 附近使用的正确语法= 1) as total_active_users, (SELECT co' at line 1 (SQL: select cloudsubscriptions.service_name, service_type.name as service_type, (SELECT count(cloudsubscriptions.id) FROM 'cloudsubscriptions' WHERE 'is_subscribe' = 1) 作为 total_active_users，(SELECT count(cloudsubscriptions.id) FROM 'cloudsubscriptions' WHERE 'is_subscribe' = 0) 作为 total_inactive_users，(SELECT count(cloudsubscriptions.id) FROM 'cloudsubscriptions') 作为来自 cloudsubscriptions 的 total_users内连接servicescloudsubscriptions.service_name=services.name内连接service_typeservices.service_type=service_type.id.id@987 @ order by service_name asc limit 15 offset 0) ◀"

请问如何解决？

Answer 1

错误是由原始表达式中的表名和列名周围的单引号引起的。

删除它们或使用反引号：

$subscribers= Cloudsubscriptions::join("services","cloudsubscriptions.service_name","=","services.name")
    ->join("service_type","services.service_type","=","service_type.id")
    ->select("cloudsubscriptions.service_name"
            ,"service_type.name as service_type"
            ,DB::raw("(SELECT count(cloudsubscriptions.id) FROM `cloudsubscriptions` WHERE `is_subscribe` = 1) as total_active_users")
            ,DB::raw("(SELECT count(cloudsubscriptions.id) FROM `cloudsubscriptions` WHERE `is_subscribe` = 0) as total_inactive_users")
            ,DB::raw("(SELECT count(cloudsubscriptions.id) FROM `cloudsubscriptions`) as total_users"))
    ->groupBy("cloudsubscriptions.service_name")                ^                  ^
->get();