从堆栈导航器中删除屏幕

Question

我观察到后退按钮逻辑可以查看堆栈中的屏幕序列。我在堆栈导航器中放置了一个抽屉导航器。

在堆栈顶部，我有启动画面。在仪表板上，当我按下后退按钮时，我需要启动屏幕。

进入应用程序后如何从堆栈中删除启动画面，所以当我按下返回按钮仪表板时，它将退出应用程序而不是进入启动画面。

/* @flow */

import React from "react";
import { Platform, Text } from "react-native";
import { Root } from "native-base";
import { StackNavigator, DrawerNavigator} from "react-navigation";
import Register from "./components/Register";
import Available from "./components/Available";
import Splash from "./components/splash/“;
import SideBar from "./components/sidebar";
import Discover from "./components/Discover/";
import Dashboard from "./components/Dashboard/";
import Contact from "./components/Contact"



const Drawer = DrawerNavigator(
  {
    Dashboard: { screen: Dashboard },
    Discover: { screen: Discover },
    Contact: { screen: Contact},
      },
  {
    navigationOptions: {
      gesturesEnabled: false,
    },
   initialRouteName: "Dashboard",
    contentOptions: {
      activeTintColor: "#e91e63"
    },
    drawerPosition: 'right',
    contentComponent: props => <SideBar {...props} />
  }
);


const AppNavigator = StackNavigator(
    {
      Splash: { screen: Splash },
      Drawer: { screen: Drawer },                           
      Available: { screen: Available },
        Register: { screen: Register },
    },
    {
       //  initialRouteName: “Splash”,
         headerMode: "none",
    }
);

export default () =>
    <Root>
        <AppNavigator />
    </Root>;

Answer 1

一种解决方案是重置初始屏幕组件内的堆栈并将用户重定向到您喜欢的屏幕：

import { NavigationActions } from 'react-navigation'

const resetAction = NavigationActions.reset({
  index: 0,
  actions: [
    NavigationActions.navigate({ routeName: 'Drawer'})
  ]
})
this.props.navigation.dispatch(resetAction)

对于较新版本的react-navigation：

import { StackActions, NavigationActions } from 'react-navigation';

const resetAction = StackActions.reset({
  index: 0,
  actions: [NavigationActions.navigate({ routeName: 'Profile' })],
});
this.props.navigation.dispatch(resetAction);

Link to the official documentation

Answer 2

最简单的解决方案之一是用新屏幕替换当前屏幕，这样用户就不会被允许返回。

const SplashScreen: () => {
    ...
  navigation.replace("LoginScreen"); // Move forward and Remove this screen from stack

见https://reactnavigation.org/docs/stack-actions/#replace

Answer 3

我用this解决了这个问题

代码：

const prevGetStateForActionHomeStack = HomeStack.router.getStateForAction;
HomeStack.router = {
  ...HomeStack.router,
  getStateForAction(action, state) {
    if (state && action.type === 'ReplaceCurrentScreen') {
      const routes = state.routes.slice(0, state.routes.length - 1);
      routes.push(action);
      return {
        ...state,
        routes,
        index: routes.length - 1,
      };
    }
    return prevGetStateForActionHomeStack(action, state);
  },
};
replaceScreen = () => {
  const { locations, position } = this.props.navigation.state.params;
  this.props.navigation.dispatch({
    key: 'NearMeMap',
    type: 'ReplaceCurrentScreen',
    routeName: 'NearMeMap',
    params: { locations, position },
  });
};

另外，如果您需要深入解释代码，请观看此短视频here

Answer 4

在 react-navigation 5.x 版本中。如果要打开新屏幕并删除以前的堆栈屏幕，可以编写：-

navigation.dispatch(StackActions.replace('screen_name', {params: {}}));

replace 动作允许替换处于导航状态的路线。您可以将其导入为：-

import { StackActions } from '@react-navigation/native';

如果您想对堆栈导航执行其他操作，请查看此链接- https://reactnavigation.org/docs/stack-actions

Answer 5

useEffect(() => {
setTimeout(() => {
  navigation.reset({
    index:0,
    routes:[
      {
        name:"Welcome",
      //  params:{key:'param'},
      },
    ],
  });
}, 1000);},[]);

你也可以像这样触发 this onPress：

onPress={()=>navigation.reset({
    index:0,
    routes:[
      {
        name:"NameOfScreen",
      //  params:{key:'param'},
      },
    ],
  })}