【问题标题】:SecretClient class in azure-keyvault-secrets python package throws unexpected errirazure-keyvault-secrets python 包中的 SecretClient 类引发意外错误
【发布时间】:2023-03-15 21:40:02
【问题描述】:

我一直在尝试让我的 python 脚本从 Azure 密钥保管库中检索机密。对于身份验证,我一直在使用 ServicePrincipal 凭据和带有 SecretClient 类的 Azure-keyvault-secrets 包。但它抛出了一个错误,这可能是因为 python 包中的任何更新。 谁能指出出了什么问题?

from azure.common.credentials import ServicePrincipalCredentials

from azure.keyvault.secrets import SecretClient

CLIENT_ID '...' #app_id
TENANT_ID = '...'
KEY = '...'


credentials = ServicePrincipalCredentials(
    client_id=CLIENT_ID,
    secret=KEY,
    tenant=TENANT_ID
)
vault_url = '...'
secret_name = "..."
secret_version = '...'


client = SecretClient(vault_url=vault_url, credential=credentials)
secret = client.get_secret(secret_name)

它给出了以下错误:

Traceback (most recent call last):
  File "key-vault.py", line 23, in <module>
    secret = client.get_secret("cromaprivate128")
  File "/Users/rishavputatunda/Library/Python/3.7/lib/python/site-packages/azure/core/tracing/decorator.py", line 71, in wrapper_use_tracer
    return func(*args, **kwargs)
  File "/Users/rishavputatunda/Library/Python/3.7/lib/python/site-packages/azure/keyvault/secrets/_client.py", line 71, in get_secret
    **kwargs
  File "/Users/rishavputatunda/Library/Python/3.7/lib/python/site-packages/azure/keyvault/secrets/_shared/_generated/v7_0/operations/_key_vault_client_operations.py", line 1621, in get_secret
    pipeline_response = self._client._pipeline.run(request, stream=False, **kwargs)
  File "/Users/rishavputatunda/Library/Python/3.7/lib/python/site-packages/azure/core/pipeline/_base.py", line 208, in run
    return first_node.send(pipeline_request)  # type: ignore
  File "/Users/rishavputatunda/Library/Python/3.7/lib/python/site-packages/azure/core/pipeline/_base.py", line 80, in send
    response = self.next.send(request)
  File "/Users/rishavputatunda/Library/Python/3.7/lib/python/site-packages/azure/core/pipeline/_base.py", line 80, in send
    response = self.next.send(request)
  File "/Users/rishavputatunda/Library/Python/3.7/lib/python/site-packages/azure/core/pipeline/_base.py", line 80, in send
    response = self.next.send(request)
  File "/Users/rishavputatunda/Library/Python/3.7/lib/python/site-packages/azure/core/pipeline/policies/_redirect.py", line 157, in send
    response = self.next.send(request)
  File "/Users/rishavputatunda/Library/Python/3.7/lib/python/site-packages/azure/core/pipeline/policies/_retry.py", line 418, in send
    response = self.next.send(request)
  File "/Users/rishavputatunda/Library/Python/3.7/lib/python/site-packages/azure/keyvault/secrets/_shared/challenge_auth_policy.py", line 67, in send
    self._handle_challenge(request, challenge)
  File "/Users/rishavputatunda/Library/Python/3.7/lib/python/site-packages/azure/keyvault/secrets/_shared/challenge_auth_policy.py", line 91, in _handle_challenge
    access_token = self._credential.get_token(scope)
AttributeError: 'ServicePrincipalCredentials' object has no attribute 'get_token'

【问题讨论】:

标签: python azure azure-keyvault


【解决方案1】:

我们不能使用 ServicePrincipalCredentials 创建 SecretClient。因为 ServicePrincipalCredentials 无法提供访问令牌。如果您想访问密钥保管库,请尝试使用 sdk azure.identity 提供的凭据。

例如 1. 使用 Azure CLI 创建服务主体

az login
az ad sp create-for-rbac -n "MyApp"   --sdk-auth

  1. 设置访问策略
az keyvault set-policy -n <your-unique-keyvault-name> --spn <clientId-of-your-service-principal> --secret-permissions delete get list set --key-permissions create decrypt delete encrypt get list unwrapKey wrapKe
  1. 代码
from azure.identity import ClientSecretCredential
    from azure.keyvault.secrets import SecretClient
tenant_id="<your sp tenant>" 
client_id="<your sp client id>"
client_secret="<your sp client secret>"
credential = ClientSecretCredential(tenant_id, client_id, client_secret)

 secret_client = SecretClient(vault_url="https://my-key-vault.vault.azure.net/", credential=credential)

 secret = secret_client.get_secret("secret-name")

    print(secret.name)
    print(secret.value)

【讨论】:

  • @RishavPutatunda 既然你的问题已经解决了,请问accept the answer好吗?它可能会帮助更多的人。
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