我怎样才能将它从一张桌子存储到另一张桌子？

Question

嗨，我正在使用 Laravel 7，并且在将表的 id 存储在另一个表上时处理了一些问题。我有一个名为 customers 的表和另一个名为 contacts 的表，其中一个客户可能有很多联系人，而一个联系人只属于一个客户。

客户.php：

public function contacts(){
        return $this->hasMany(Contact::class);
    }

这是我建立关系的方法联系人。

以下是我在 Contact.php 中的客户方法：

public function customer(){
        return $this->belongsTo(Customer::class,'id_account','id'); 
    }

在我的联系人表中，我有一个名为 id_account 的列，我希望在那里存储客户 ID。所以我试图通过执行以下操作来实现这一点：

namespace App\Http\Controllers\Backend;

use Illuminate\Http\Request;
use App\Model\Contact;
use App\Model\Customer;
use App\Http\Controllers\Controller;
use Auth;
use Session;


class ContactController extends Controller
{
    //
    public function view(){ 
        $allData = Contact::all();
        return view('backend.contact.view-contact', compact('allData'));
    }

    public function add(){ 
        $customers = Customer::all();
        $contact['customers'] = Customer::all();
        
        return view('backend.contact.add-contact', compact('customers'));
    }

    public function store(Request $request){
        $customers = Customer::all();
        $contact = new Contact();
        $contact->name = $request->name;
        $contact->lastname = $request->lastname;
        $contact->id_account = Customer::contacts('id');
        $contact->idOwner = Auth::user()->id;
        $contact->position = $request->position;
        $contact->mobile_no = $request->mobile_no;
        $contact->email = $request->email;
        $contact->save();
        Session::flash('success');
        return redirect()->route('contact.view', compact('contact','customers'));
    }
}

我尝试了几种方法，例如：

$contact->id_account = Customer::contacts('id');

或者

$contact->id_account = Customer::get('id');

$contact->id_account = $request->$customers->id;

但是这些都不起作用，我是 Laravel 的新手，我真的在为这个问题苦苦挣扎。不同类型的错误是：

Invalid datetime format: 1366 Incorrect integer value: '[{"id":1}]' for column `axis`.`contacts`.`id_account` at row 1 (SQL: insert into `contacts` (`name`, `lastname`, `id_account`, `idOwner`, `position`, `mobile_no`, `email`, `updated_at`, `created_at`) values (Mateo, Ghidini, [{"id":1}], 1, pasante, 12345678, mateo.ghidini@hotmail.com, 2021-08-05 18:31:12, 2021-08-05 18:31:12))

另一个错误：

Trying to get property 'id' of non-object

最后：

Non-static method App\Model\Customer::contacts() should not be called statically



<div class="form-group col-md-6">
               <label for="account">Cuenta</label>
                <select name="account" id="" class="form-control">
                     <option value="">Seleccione el holding de la empresa</option>
                     @foreach ($customers as $key => $customer)
                     <option value="{{$customer->id}}">{{$customer->holding}}</option>
                                
                      @endforeach
                </select>
           </div>

Answer 1

当您尝试保存时，您需要确切知道要在该行中存储哪个Customer 的 ID。因此，您可以在表单上显示<select ...> 并让用户选择Customer

在resources/views/backend/contact/add-contact.blade.php

<!-- I assume you have a form and other inputs here -->
<form>

<!-- add a select-option for Customer -->
<select name="customer_id">
    @foreach($customers as $customer)
    <option value="{{ $customer->id }}">
        {{ $customer->name }}
    </option>
    @endforeach
</select>


</form>

现在您可以从控制器中使用它

public function store(Request $request){
    $customers = Customer::all();
    $contact = new Contact();
    $contact->name = $request->name;
    $contact->lastname = $request->lastname;
    $contact->id_account = $request->customer_id; // here we used customer_id from form
    $contact->idOwner = Auth::user()->id;
    $contact->position = $request->position;
    $contact->mobile_no = $request->mobile_no;
    $contact->email = $request->email;
    $contact->save();
    Session::flash('success', 'Contact saved to selected customer.');
    return redirect()->route('contact.view', compact('contact','customers'));
}