根据 MA​​X DATE 获取所有列的不同结果

Question

使用 SQL Server 2012

我已经看到了一些关于这个主题的主题，但我找不到一个涉及查询中的多个连接的主题。我无法在此数据库上创建 VIEW，因此需要连接。

查询

SELECT 

      p.Price
      ,s.Type
      ,s.Symbol
      , MAX(d.Date) Maxed
  FROM AdventDW.dbo.FactPrices p
  INNER JOIN dbo.DimSecurityMaster s
  ON s.SecurityID = p.SecurityID
  INNER JOIN dbo.DimDateTime d
   ON
  p.DateTimeKey = d.DateTimeKey
  GROUP BY p.Price ,
           s.Type ,
           s.Symbol
ORDER BY s.Symbol

查询有效，但不会产生不同的结果。我正在使用 Order by 来验证结果，但是一旦我让它工作就不需要它了。 I 结果集如下所示。

Price   Type    Symbol  Maxed
10.57   bfus    *bbkd           3/31/1989
10.77   bfus    *bbkd           2/28/1990
100.74049   cbus    001397AA6       8/2/2005
100.8161    cbus    001397AA6       7/21/2005

我想要的结果集是

Price   Type    Symbol  Maxed
10.77   bfus    *bbkd           2/28/1990
100.74049   cbus    001397AA6       8/2/2005

这是我尝试过的其他一些 StackOverflow 线程，但无法处理我的特定查询

How can I SELECT rows with MAX(Column value), DISTINCT by another column in SQL?

SQL Selecting distinct rows from multiple columns based on max value in one column

Answer 1

    /* 
    this is your initial select which is fine because this is base from your original criteria, 
I cannot ignore this so i'll keep this in-tact. Instead from here i'll create a temp
    */

  SELECT 
      p.Price
      , s.Type
      , s.Symbol
      , MAX(d.Date) Maxed
  INTO #tmpT
  FROM AdventDW.dbo.FactPrices p
  INNER JOIN dbo.DimSecurityMaster s
      ON s.SecurityID = p.SecurityID
  INNER JOIN dbo.DimDateTime d
      ON p.DateTimeKey = d.DateTimeKey
  GROUP BY p.Price ,
       s.Type ,
       s.Symbol
  ORDER BY s.Symbol

SELECT innerTable.Price, innerTable.Symbol, innerTable.Type, innerTable.Maxed 
FROM (

   SELECT
      ROW_NUMBER () OVER (PARTITION BY t1.Symbol, t1.Type, t1.Maxed ORDER BY t1.Maxed DESC) as row 
      , *
   FROM #tmpT AS t1
) AS innerTable
WHERE row = 1

DROP TABLE #tmpT

Answer 2

您应该使用派生表，因为您真的只想对 DateTimeKey 表进行分组以获取 MAX 日期。

SELECT p.Price ,
       s.Type ,
       s.Symbol ,
       tmp.MaxDate
FROM AdventDW.dbo.FactPrices p
INNER JOIN dbo.DimSecurityMaster s ON s.SecurityID = p.SecurityID
INNER JOIN
  ( SELECT MAX(d.Date) AS MaxDate ,
           d.DateTimeKey
   FROM dbo.DimDateTime d
   GROUP BY d.DateTimeKey ) tmp ON p.DateTimeKey = tmp.DateTimeKey
ORDER BY s.Symbol;

Answer 3

如果您想要最大日期的数据，请使用row_number() 而不是group by：

SELECT ts.*
FROM (SELECT p.Price, s.Type, s.Symbol, d.Date,
             ROW_NUMBER() OVER (PARTITION BY s.Type, s.Symbol
                                ORDER BY d.Date DESC
                               ) as seqnum
      FROM AdventDW.dbo.FactPrices p INNER JOIN
           dbo.DimSecurityMaster s
           ON s.SecurityID = p.SecurityID INNER JOIN
           dbo.DimDateTime d
           ON p.DateTimeKey = d.DateTimeKey
     ) ts
WHERE seqnum = 1
ORDER BY s.Symbol;