使用 where 子句检索数据时，无论如何要检索计数 0 吗？ (Laravel 雄辩)答案

【问题标题】：Is there anyway to retrieve count 0 when retrieve data using where clause? (Laravel Eloquent)使用 where 子句检索数据时，无论如何要检索计数 0 吗？ (Laravel 雄辩)
【发布时间】：2022-01-12 15:46:23
【问题描述】：

我目前正在使用 group by 检索数据，以获得相同的宝藏名称、找到的总数和相同的宝藏数量（上限）。使用下面的代码，我可以得到所有的宝物数据，但是当宝物被完全认领时，它无法显示total_left为0。

*claimed 列是一个布尔值，其中 0 尚未被声明。 *cap 是同一地点的总宝藏

查询

$treasure_hunt_data = TreasureHunt::where('claimed', '0')
                        ->selectRaw(" treasure_name, count(claimed) as total_left, cap")
                        ->groupBy(['treasure_name', 'cap'])
                        ->get();

数据

[
    {"treasure_name":"Location A","total_left":5,"cap":5},
    {"treasure_name":"Location B","total_left":2,"cap":2},
    {"treasure_name":"Location C","total_left":2,"cap":2},
    {"treasure_name":"Location D","total_left":10,"cap":10}
]

所需数据

[
    {"treasure_name":"Location A","total_left":5,"cap":5},
    {"treasure_name":"Location B","total_left":2,"cap":2},
    {"treasure_name":"Location C","total_left":2,"cap":2},
    {"treasure_name":"Location D","total_left":10,"cap":10},
    {"treasure_name":"Location E","total_left":0,"cap":1}
]

数据库数据

迁移详情

   Schema::create('treasure_hunts', function (Blueprint $table) {
        $table->id();
        $table->string('treasure_name');
        $table->boolean('claimed')->default(0);
        $table->string('cap');
        $table->timestamps();
    });

【问题讨论】：

请添加模型和迁移详细信息以及所需输出的示例数据，以便我们了解您的数据库是什么样的。
@miken32，我已经添加了迁移细节和数据库数据
请勿发布代码图片

标签： php laravel eloquent laravel-8

【解决方案1】：

您可以使用 CTE（公用表表达式）和 DB::select 语句来做到这一点。例如：

$treasure_hunt_data = DB::select("
    with treasure_data as (
        select treasure_name, count(claimed) as total_left, cap
        from treasure_hunt
        where claimed = 0 
        group by treasure_name, cap
    )
    select * from treasure_data where total_left = 0
");

这会将结果集作为数组返回。

【讨论】：

使用 where total_left = 0; 不会有数据返回没有 where total_left = 0;我们将得到 [{"treasure_name":"Location A","total_left":5,"cap":5},{"treasure_name":"Location B","total_left":2,"cap":2}, {"treasure_name":"位置 C","total_left":2,"cap":2},{"treasure_name":"位置 D","total_left":10,"cap":10}]
根据需要编辑 CTE，仅作为示例。

【解决方案2】：

以下是数据库中的实际记录：

[{"id":1,"treasure_name":"Location A","claimed":1,"cap":"10","created_at":null,"updated_at":null},
{"id":2,"treasure_name":"Location B","claimed":1,"cap":"220","created_at":null,"updated_at":null},
{"id":3,"treasure_name":"Location C","claimed":1,"cap":"42","created_at":null,"updated_at":null},
{"id":4,"treasure_name":"Location D","claimed":0,"cap":"23","created_at":null,"updated_at":null},
{"id":5,"treasure_name":"Location A","claimed":1,"cap":"233","created_at":null,"updated_at":null}]

试试这个查询来检索数据：

$treasure_hunt_data = TreasureHunt::select(
            'treasure_name',
            \DB::raw('sum(case when claimed = 1 then 1 else 0 end) as total_left'), 
            \DB::raw('sum(cap) as cap')
        )
        ->groupBy('treasure_name')
        ->get();

以下是上述查询的结果：

[{"treasure_name":"Location A","total_left":"2","cap":243},
{"treasure_name":"Location B","total_left":"1","cap":220},
{"treasure_name":"Location C","total_left":"1","cap":42},
{"treasure_name":"Location D","total_left":"0","cap":23}]

【讨论】：

是的，这项工作，但需要对其进行一些修改