如何使用 Laravel 5.1 执行原始查询？

Question

所以我有这个小查询要在我的数据库上运行，它在 MySQL Workbench 中运行良好。 基本上，一个带有 LEFT JOIN 的 SELECT 和一个带有 LEFT JOIN 的 UNION。

SELECT
    cards.id_card,
    cards.hash_card,
    cards.`table`,
    users.name,
    0 as total,
    cards.card_status,
    cards.created_at
FROM cards
LEFT JOIN users
ON users.id_user = cards.id_user
WHERE hash_card NOT IN ( SELECT orders.hash_card FROM orders )
UNION
SELECT
    cards.id_card,
    orders.hash_card,
    cards.`table`,
    users.name,
    sum(orders.quantity*orders.product_price) as total, 
    cards.card_status, 
    max(orders.created_at) 
FROM menu.orders
LEFT JOIN cards
ON cards.hash_card = orders.hash_card
LEFT JOIN users
ON users.id_user = cards.id_user
GROUP BY hash_card
ORDER BY id_card ASC

In 试图将其翻译成 Laravel，但没有成功。

$cards = Card::selectRaw('cards.id_card, cards.hash_card ,cards.table, users.name, 0 as total, cards.card_status, cards.created_at as last_update')
                ->leftJoin('users','users.id_user','=','cards.id_user')
                ->whereNotIn( 'hash_card', Order::select('orders.hash_card')->get() )
                ->union(
                        Order::selectRaw('cards.id_card, orders.hash_card, cards.table, users.name, sum(orders.quantity*orders.product_price) as total, cards.card_status, max(orders.created_at) as last_update')
                        ->leftJoin('cards','cards.hash_card','=','orders.hash_card')
                        ->leftJoin('users','users.id_user','=','cards.id_user')
                )
                ->groupBy('hash_card')
                ->orderBy('cards.id_card','asc')
                ->get();

我收到了错误

Builder.php 第 1249 行中的 ErrorException：未定义的属性： Illuminate\Database\Eloquent\Builder::$bindings

我如何在 Laravel 中执行一个完全原始的查询或在 Laravel 中以正确的方式编写查询？

Answer 1

我在this topic 中找到了解决方案，并编写了以下代码：

$cards = DB::select("SELECT
        cards.id_card,
        cards.hash_card,
        cards.`table`,
        users.name,
        0 as total,
        cards.card_status,
        cards.created_at as last_update
    FROM cards
    LEFT JOIN users
    ON users.id_user = cards.id_user
    WHERE hash_card NOT IN ( SELECT orders.hash_card FROM orders )
    UNION
    SELECT
        cards.id_card,
        orders.hash_card,
        cards.`table`,
        users.name,
        sum(orders.quantity*orders.product_price) as total, 
        cards.card_status, 
        max(orders.created_at) last_update 
    FROM menu.orders
    LEFT JOIN cards
    ON cards.hash_card = orders.hash_card
    LEFT JOIN users
    ON users.id_user = cards.id_user
    GROUP BY hash_card
    ORDER BY id_card ASC");

Answer 2

    DB::statement("your query")

我用它为迁移中的列添加索引

Answer 3

来自 Laravel 文档的示例：

$users = DB::table('users')
    ->selectRaw('count(*) as user_count, status')
    ->where('status', '<>', 1)
    ->groupBy('status')
    ->get();

另一个例子：

$products = DB::table('products')
    ->leftjoin('category','category.product_id','=','products.id')
    ->selectRaw('COUNT(*) as nbr', 'products.*')
    ->groupBy('products.id')
    ->get();

另一个例子——我们甚至可以在同一个语句中执行 avg() 和 count()。

$salaries = DB::table('salaries')
    ->selectRaw('companies.name as company_name, avg(salary) as avg_salary, count(*) as people_count')
    ->join('companies', 'salaries.company_id', '=', 'companies.id')
    ->groupBy('companies.id')
    ->orderByDesc('avg_salary')
    ->get();

学分： https://blog.quickadminpanel.com/5-ways-to-use-raw-database-queries-in-laravel/

Answer 4

您也可以像这样运行原始查询。

DB::table('setting_colleges')->first();