【问题标题】:Python web scraping style contentPython网页抓取样式内容
【发布时间】:2019-07-19 07:59:35
【问题描述】:
我只想使用python从HTML中提取数据。(我需要data = 20%)
对此的任何帮助将不胜感激。
<div class="ratings-container">
<div class="ratings">
<div class="ratings active" style="width: 20%"></div>
</div>
</div>
我不知道如何获取样式内容。以下类似代码的结果为NULL:
mratingNew = (tag.findAll('div',attrs={"class":"ratings active"}))
for i in range(len(muserName)):
print(mratingNew[i].['style'])
【问题讨论】:
标签:
python-3.x
web-scraping
beautifulsoup
jupyter-notebook
html-parsing
【解决方案1】:
您可以使用find获取宽度,并可以根据:拆分它
from bs4 import BeautifulSoup
html = '''<div class="ratings-container">
<div class="ratings">
<div class="ratings active" style="width: 20%"></div>
</div>
</div>'''
soup = BeautifulSoup(html,"html.parser")
finddiv = soup.find('div',attrs={'class':'ratings active'})
style = finddiv['style']
style = style.split(':',1)[-1]
print style
输出:
20%
如果您有多个具有相同类名的宽度,例如:
html = '''<div class="ratings-container">
<div class="ratings">
<div class="ratings active" style="width: 20%"></div>
<div class="ratings active" style="width: 40%"></div>
<div class="ratings active" style="width: 30%"></div>
</div>
</div>'''
需要使用findAll,并一一拆分
find_last_div = soup.findAll('div',attrs={'class':'ratings active'})
for width_value in find_last_div:
width_Get = width_value['style'].split(':',1)[-1]
print width_Get
输出:
20%
40%
30%