【发布时间】:2014-10-12 05:29:55
【问题描述】:
我有一个简单的表格,其中存储评论以及评分如下:
Create table tblReview
(
Id int primary key identity,
Rating smallint,
Review nvarchar(max),
RegistrationId int foreign key references tblAllRegisteredBusiness(RegistrationId),
ReviewDate DateTime not null Default GetDate()
)
我有一个带有 AJAX 星级评分控件的 gridview。我要做的就是使用基于 RegistrationId 的所有评论填充 gridview。gridview 如下所示:
<asp:GridView ID="GridView1" runat="server" GridLines="None" AutoGenerateColumns="False" ShowHeader="False" Width="618px" OnRowDataBound="GridView1_RowDataBound">
<Columns>
<asp:TemplateField>
<ItemTemplate>
<table cellpadding="0" cellspacing="0" class="auto-style12">
<tr>
<td class="auto-style58"></td>
<td class="auto-style61"> <ajax:Rating ID="rating2" AutoPostBack="true" runat="server" StarCssClass="ratingEmpty" WaitingStarCssClass="ratingSaved" EmptyStarCssClass="ratingEmpty" FilledStarCssClass="ratingFilled"></ajax:Rating> </td>
<td class="auto-style59" style="vertical-align:bottom"> <span class="auto-style11">Review by:</span><asp:Label ID="lblUser" runat="server" CssClass="auto-style11"></asp:Label>
<span class="auto-style11"> on </span>
<asp:Label ID="lblDateTime" runat="server" style="font-size: small" Text="<%# Bind('ReviewDate') %>"></asp:Label>
</td>
<td class="auto-style60"></td>
</tr>
<tr>
<td class="auto-style56"> </td>
<td class="auto-style57" colspan="2">
<asp:Label ID="lblReview" runat="server" Text="<%# Bind('Review') %>"></asp:Label>
</td>
<td> </td>
</tr>
<tr>
<td class="auto-style56"> </td>
<td class="auto-style57" colspan="2"> </td>
<td> </td>
</tr>
</table>
</ItemTemplate>
</asp:TemplateField>
</Columns>
</asp:GridView>
我尝试将评分绑定如下:
<ajax:Rating ID="rating2" CurrentRating=<%# Rating %>
但不起作用。所以我想到了使用gridview的rowdatabound事件来绑定评级如下:
protected void GridView1_RowDataBound(object sender, GridViewRowEventArgs e)
{
if (e.Row.RowType == DataControlRowType.DataRow)
{
string CS = ConfigurationManager.ConnectionStrings["IndiaLystConnectionString"].ConnectionString;
using (SqlConnection con = new SqlConnection(CS))
{
con.Open();
SqlCommand cmd = new SqlCommand("Select Rating from tblReview where RegistrationId=@RegistrationId", con);
cmd.Parameters.AddWithValue("@RegistrationId", lblId.Text);
SqlDataReader rdr = cmd.ExecuteReader();
rdr.Read();
AjaxControlToolkit.Rating star = (AjaxControlToolkit.Rating)GridView1.FindControl("rate2");
star.CurrentRating = Convert.ToInt32(rdr["Rating"].ToString());
}
}
}
这又不起作用了。那么在这种情况下我应该怎么做。我认为这很简单,但结果却是一项艰巨的任务。
【问题讨论】:
标签: c# asp.net ajax gridview rating