【发布时间】:2015-03-04 05:18:00
【问题描述】:
谁能解释我如何禁用链接(仅禁用因为我必须重新启用链接)我曾尝试使用此document.getElementById("aadd").href = "Detail.aspx?using=add"; 但是当我动态加载列表元素时我不能这样做。因为我问你我怎样才能禁用一个链接,所以我不能使用它并重新启用它?
function changebuttonstate(thisbtn) {
if (document.getElementById("add").disabled == true) {
document.getElementById("add").disabled = false;
document.getElementById("aadd").href = "Detail.aspx?using=add";
var elems = document.getElementsByClassName("disabledbutton");
for (var i = 0; i < elems.length; i++) {
elems[i].disabled = false;
}
} else {
document.getElementById("add").disabled = true;
document.getElementById("aadd").href = "#";
var elems = document.getElementsByClassName("disabledbutton");
for (var i = 0; i < elems.length; i++) {
elems[i].disabled = true;
}
thisbtn.disabled = false;
}
if (document.getElementById("refresh").disabled == true) {
document.getElementById("refresh").disabled = false;
document.getElementById("arefresh").href = "";
var elems = document.getElementsByClassName("disabledbutton");
for (var i = 0; i < elems.length; i++) {
elems[i].disabled = false;
}
} else {
document.getElementById("refresh").disabled = true;
document.getElementById("arefresh").href = "#";
var elems = document.getElementsByClassName("disabledbutton");
for (var i = 0; i < elems.length; i++) {
elems[i].disabled = true;
}
thisbtn.disabled = false;
}
}
<a href="Detail.aspx?using=edit&id={{x.ID}}"><input type="button" id="Edit" value="Edit" class="btn btn-primary disabledbutton"/></a>
<button type="button" class="btn btn-danger disabledbutton" data-toggle="collapse" data-target="#demo{{x.ID}}" onclick="changebuttonstate(this)">Delete</button>
<div id="demo{{x.ID}}" class="collapse disabledbutton">
<div class="well">
<p>Are you sure?</p>
<a href="Delete.aspx?id={{x.ID}}"><input type="button" id="Button1" class="btn btn-danger" value="Delete"/></a>
</div>
</div>
<a href="Detail.aspx?using=add" id="aadd"><input type="button" id="add" value="Add" class="btn btn-success"/></a>
<a href="listview.aspx" id="arefresh"><input type="button" id="refresh" value="Refresh" class="btn btn-primary"/></a>
【问题讨论】:
-
旁注:我可以看到您在
a中有一个input,这是无效的。 -
我没有说它行不通。我说这是无效标记。嵌套两个可点击元素有什么意义?你点击一个,你点击了两个。
-
你的代码有什么问题是它不起作用吗?
-
您正确禁用了输入,但
<a>标签没有禁用属性,您可以阻止<a>标签的默认操作 -
@FlorianHofmeister 您可能应该完全摆脱
<a>标签,而只使用<input>
标签: javascript html asp.net twitter-bootstrap