我应该使用什么“逻辑查询运算符/s”来合并两个单独的查询？

Question

我使用什么 Logical Query Operator/s 来加入 两个 查询，生成属于 登录用户 Meteor.userId(); AND在recipientNumber 变量中具有登录用户的电话号码的所有文档。

文档在recipientNumber 变量中包含登录用户电话号码，表明登录用户是收件人资金。

作为参考，请在下面找到登录用户详细信息：

var user = Meteor.userId();      
var userDetails = Meteor.users.findOne({_id: user}, { fields: { "profile.telephoneNumber": 1, "profile.name": 1 } } ); 

var usersNumber = userDetails.profile.telephoneNumber;
var userName = userDetails.profile.name;

console.log("Users _id is: " +user);
console.log("Users Number is: " +usersNumber);
console.log("Users Name is: " +userName);

上面的代码正确产生：

Users _id is: "sxY3fsY9LmJYqFkiG"
Users Number is: +254705086633
Users Name is: Sir.BT

recipientsDetails.find({ }).fetch(); 显示主题中集合的内容：

0:
payersName: "The LucidOreo"
payersUserId: "KDJFGkCRF3E5nY37e"
recipientNumber: "+254705086633"
_id: "MMyinrcrrYpz2haxq"    
1:
payersName: "Sir.BT"
payersUserId: "sxY3fsY9LmJYqFkiG"
recipientNumber: "+254705086633"
_id: "YbPFT9ecCA4FTgqsn"

2:
payersName: "Sir.BT"
payersUserId: "sxY3fsY9LmJYqFkiG"
recipientNumber: "+254705577633"
_id: "ZPWNsQ7TWSJcERSJv"

下面的查询过滤集合，根据用户 Meteor.userId() 仅显示属于用户的文档：sxY3fsY9LmJYqFkiG。

var user = Meteor.userId(); 
recipientsDetails.find( {payersUserId: user} ).fetch();

在结果下方查找：

0:
payersName: "Sir.BT"
payersUserId: "sxY3fsY9LmJYqFkiG"
recipientNumber: "+254705086633"
_id: "YbPFT9ecCA4FTgqsn"


1:
payersName: "Sir.BT"
payersUserId: "sxY3fsY9LmJYqFkiG"
recipientNumber: "+254705577633"
_id: "ZPWNsQ7TWSJcERSJv"

我想制定一个显示两个事物组合的查询：

属于登录用户的所有文档（如下代码所示）：

var user = Meteor.userId(); 
recipientsDetails.find( {payersUserId: user} ).fetch();

...以及所有带有登录用户电话号码的文件（如下代码所示）：

var user = Meteor.userId();      
 var userDetails = Meteor.users.findOne({_id: user}, { fields {"profile.telephoneNumber": 1 } } ); 

 var usersNumber = userDetails.profile.telephoneNumber;

 recipientsDetails.find( {recipientNumber: usersNumber} ).fetch();

我应该在查询中使用什么逻辑查询运算符来产生这个？

我试过了：

var user = Meteor.userId();

var userDetails = Meteor.users.findOne({_id: user}, { fields: { "profile.telephoneNumber": 1 } } ); 

var usersNumber = userDetails.profile.telephoneNumber; 

recipientsDetails.find( { $and: [{payersUserId: user},  {recipientNumber: usersNumber }  ] }  ).fetch();

不幸的是，这错误地产生了：

0:
payersName: "Sir.BT"
payersUserId: "sxY3fsY9LmJYqFkiG"
recipientNumber: "+254705086633"
_id: "YbPFT9ecCA4FTgqsn"

1:
payersName: "Sir.BT"
payersUserId: "sxY3fsY9LmJYqFkiG"
recipientNumber: "+254705577633"
_id: "ZPWNsQ7TWSJcERSJv"

...然后省略：

payersName: "The LucidOreo"
payersUserId: "KDJFGkCRF3E5nY37e"
recipientNumber: "+254705086633"
_id: "MMyinrcrrYpz2haxq"

...明显带有recipientNumber: "+254705086633"登录用户数。

为了澄清，期望的产量是：

0:
payersName: "The LucidOreo"
payersUserId: "KDJFGkCRF3E5nY37e"
recipientNumber: "+254705086633"
_id: "MMyinrcrrYpz2haxq"    
1:
payersName: "Sir.BT"
payersUserId: "sxY3fsY9LmJYqFkiG"
recipientNumber: "+254705086633"
_id: "YbPFT9ecCA4FTgqsn"

2:
payersName: "Sir.BT"
payersUserId: "sxY3fsY9LmJYqFkiG"
recipientNumber: "+254705577633"
_id: "ZPWNsQ7TWSJcERSJv"

谁能向我解释一下为什么省略了这个以及如何更好地制定主题中的查询？

Answer 1

如果您替换以下内容，我相信它应该可以工作：

recipientsDetails.find( { $and: [{payersUserId: user},  {recipientNumber: usersNumber }  ] }  ).fetch();

与

recipientsDetails.find( { $or: [{payersUserId: user},  {recipientNumber: usersNumber }  ] }  ).fetch();