【发布时间】:2011-03-14 09:09:53
【问题描述】:
我已经成功地让我的低级鼠标挂钩代码工作,但我观察到的一些行为我不太理解。如果我生成一个安装鼠标钩的线程,一切正常。当我不再需要它运行时,我让线程在退出程序时自动销毁,我想我可以轻松地显式终止线程。然而,这让我感到不安,因为我最终不会调用UnhookWindowsHookEx 来释放鼠标挂钩资源。
所以我试图颠倒我的测试程序中的逻辑。我尝试生成一个休眠一段时间的线程,然后写入全局变量。然后我从主线程调用钩子安装例程。这里是一个循环,它检查全局变量并在适当的时候退出循环。然后它将能够自行清理。以下是相关代码:
static int willQuit = 0;
unsigned WINAPI MouseProcessingProc (void *param) {
try { // will catch exceptions and not propagate them
HHOOK mousehook = SetWindowsHookEx(WH_MOUSE_LL, MouseHookProc,
NULL, 0);
if (mousehook == NULL) printf("Mousehook error %u\n",GetLastError());
while(true) {
MSG msg;
if (GetMessage(&msg,0,0,0)) {
TranslateMessage(&msg);
DispatchMessage(&msg);
}
if (willQuit) { printf("willQuit no longer 0!\n"); break; }
printf("Looped\n");
}
willQuit = 0;
UnhookWindowsHookEx(mousehook);
printf("Procedure completed without exceptional events.\n");
} catch (const std::string& s) {
printf("String exception: %s\n", s.c_str());
} catch (int i) {
printf("Int exception: %d\n", i);
} catch (...) {
printf("Unknown default exception!\n");
}
printf("Exiting thread execution.\n");
return 0;
}
void spawn() {
printf("Spawning Mouse thread\n");
_beginthreadex(NULL,0,MouseProcessingThreadProc,NULL,0,0);
}
void run() {
printf("Running Mouse routine\n");
MouseProcessingThreadProc(0);
}
void stop() {
printf("Stopping Mouse routine\n");
willQuit = 1;
}
unsigned WINAPI threadproc(void *param) {
Sleep(500);
printf("Spawned thread says 3");
Sleep(500);
printf("2");
Sleep(500);
printf("1\n");
Sleep(500);
printf("Spawned thread calls stop now -->\n");
stop();
}
int main() {
_beginthreadex(NULL,0,threadproc,NULL,0,0); // waiter and stopper thread
run(); // become the mousehook thread
printf("Completed\n");
return 0;
}
现在发生的情况是,我拥有的小消息轮询循环(while 循环)从未真正从GetMessage 调用返回,因此它永远无法到达它检查willQuit 的地步。我已经用那些 printf 和 gdb 验证了这一点。为什么GetMessage 不返回?有没有更好的方法来设置我的鼠标钩线?还是我在尝试做一些我不应该做的事情?
感谢阅读。
【问题讨论】:
标签: c++ c multithreading winapi hook