C 编码有趣答案

【问题标题】：C coding interestingC 编码有趣
【发布时间】：2021-12-19 05:56:15
【问题描述】：

#include <stdio.h>

int main (void) //starting entry of integer indicate not associated with any data types argument
{
    int value1, value2, calculate = 0; //integer values
    
    printf ("\nProgram should perform the following:"); 
    printf("\n"); 
    
    printf ("\nHave the user enter two different integer numbers to be divided by the program "); 
    {

                printf ("\nIf the division of both numbers");
                printf("\n"); 
                printf ("\nresult with the remainder of zero,"); 
        
                printf("\n"); 
    
                printf ("\nby the second number.");
    
                printf("\n"); 
    
                printf ("Example: thirty-five divided by seven will have a remainder of zero"); 
    
                            printf ("\n"); 
    }
    
    printf ("Please enter the first integer number>>"); 
    scanf  ("%i", &value1);
    
    printf ("Please enter the second integer>> ");  
    scanf  ("%i", &value2); 
       
    if (value1 % value2 == 0 ) {
      
       printf ("\n%i is evenly divisible by %i\n", value1, value2);
       calculate = value1 / value2;
       printf ("%i / %i = %i\n", value1, value2, calculate);
       
       
    else
       printf ("\n%i is not evenly divisible by %i\n", value1, value2);
    

return 0;

}

我编写的这段代码工作正常。但是我似乎找不到使用哪个 else 或 else if 语句来使代码显示错误：如果用户输入的第二个数字为零，则程序中允许为零。

【问题讨论】：

这不是C#，请去掉C#标签。另外，您能否改进代码格式（提示：使用编辑器中的{} 按钮）？
你想要的错误信息不正确。仅允许输入的第一个数字为零 (value1)。 x/0 未定义，即使对于 x==0。
请发布实际可编译的代码。这个区块在哪里关闭？ if (value1 % value2 == 0 ) {

标签： c windows printf

【解决方案1】：

不要在printf 之后使用括号，它不会改变任何内容，并且在scanf 和printf 中使用%d 表示整数。并在 else 之前关闭 if 括号。

【讨论】：

【解决方案2】：

如果你想为用户引入这样的消息，你必须在用户提供输入后执行条件来检查数字。可以这样做：

#include <stdio.h>

int main(void)  //starting entry of integer indicate not associated with any data types argument
{
    int value1, value2, calculate = 0;  //integer values
    printf("\nProgram should perform the following:");
    printf("\n");
    printf("\nHave the user enter two different integer numbers to be divided by the program ");
    printf("\nIf the division of both numbers");
    printf("\n");
    printf("\nresult with the remainder of zero,");
    printf("\n");
    printf("\nby the second number.");
    printf("\n");
    printf("Example: thirty-five divided by seven will have a remainder of zero");
    printf("\n");
    printf("Please enter the first integer number>>");
    scanf("%i", &value1);
    printf("Please enter the second integer>> ");
    scanf("%i", &value2);

    if (value1 == 0 && value2 != 0)
    {
        printf("\nA zero is allowed in the program if the second number that the user enters is zero");
        return 0;
    }
    else
    {
        if (value1 % value2 == 0)
        {
            printf("\n%i is evenly divisible by %i\n", value1, value2);
            calculate = value1 / value2;
            printf("%i / %i = %i\n", value1, value2, calculate);
        }
        else
        {
            printf("\n%i is not evenly divisible by %i\n", value1, value2);
        }
    }

    return 0;
}

【讨论】：