C 程序 - 如何将 char* 数组的值分配给 2d char* 数组？

Question

我试图从 2 个字符指针数组中初始化一个 2d 数组，该数组表示一副纸牌，这些指针数组称为 faces 和 suit，表示纸牌的面孔和花色。我收到如下所示的各种错误，无法弄清楚如何正确地将值添加到我的牌组以及显示我的牌组。谁能向我指出需要更改哪些内容才能使我的代码正常工作？谢谢。

#include <stdio.h>
#include <string.h>
#include "functions.h"

char **deck[4][13];

char *suit[] = {
    "Hearts",
    "Diamonds",
    "Clubs",
    "Spades"};
char *faces[] = {
    "Ace",
    "Two",
    "Three",
    "Four",
    "Five",
    "Six",
    "Seven",
    "Eight",
    "Nine",
    "Ten",
    "Jack",
    "Queen",
    "King",
};

char** initializeDeck(char** arr)
{
    char addToString[] = " of ";
    for (int i = 0; i < 4; i++)
    {
        for (int j = 0; j < 13; j++)
        {
            arr[i][j] =  *faces[j], addToString, *suit[i]
        }
    }
    return arr;
}

void displayDeck(char** arr){
    for (int i = 0; i < 4; i++)
    {
        for (int j = 0; j < 13; j++)
        {
            printf("[%s] ", **arr[i][j]);
        }
        printf("\n");
    }
}

错误：

functions.c:35:37: warning: expression result unused [-Wunused-value]
            arr[i][j] =  *faces[j], addToString, *suit[i];
                                    ^~~~~~~~~~~
functions.c:35:50: warning: expression result unused [-Wunused-value]
            arr[i][j] =  *faces[j], addToString, *suit[i];
                                                 ^~~~~~~~
functions.c:46:30: error: indirection requires pointer operand ('int' invalid)
            printf("[%s] ", **arr[i][j]);

Answer 1

1. arr[i][j] = *faces[j], addToString, *suit[i] 没有将字符串连接在一起。

这里有一些代码，但我认为你的老师不会相信那是你的代码

char *myconcat(const char *s1, const char *s2, const char *s3)
{
    size_t len = strlen(s1) + strlen(s2) + strlen(s3);
    char *newstr = malloc(len + 1);
    
    if(newstr)
    {
        strcpy(newstr, s1);
        strcat(newstr, s2);
        strcat(newstr, s3);
    }
    return newstr;
}


char *(*initializeDeck(void))[13]
{
    char *(*cards)[13] = malloc(4 *sizeof(*cards));
    for (int i = 0; i < 4; i++)
    {
        for (int j = 0; j < 13; j++)
        {
            cards[i][j] =  myconcat(faces[j], " of ", suit[i]);
        }
    }
    return cards;
}

void displayDeck(char *(*cards)[13]){
    for (int i = 0; i < 4; i++)
    {
        for (int j = 0; j < 13; j++)
        {
            printf("[%s] ", cards[i][j]);
        }
        printf("\n");
    }
}