【发布时间】:2014-03-18 03:42:22
【问题描述】:
我正在使用 AES 对字符串进行加密,但加密后的字符串末尾包含 \n 和 \r。
public class AESImpl {
private static String decryptedString;
private static String encryptedString;
public static void main(String[] args) throws NoSuchAlgorithmException, IOException, ClassNotFoundException {
String strToEncrypt = "This text has to be encrypted";
SecretKey secretKey = generateSecretKey();
String encryptStr = encrypt(strToEncrypt, secretKey);
System.out.println("Encrypted String : " + encryptStr + "It should not come in new line");
String decryptStr = decrypt(encryptStr, secretKey);
System.out.println("Decrypted String : " + decryptStr);
}
private static SecretKey generateSecretKey() throws NoSuchAlgorithmException, IOException {
KeyGenerator kg = KeyGenerator.getInstance("AES");
kg.init(128);
SecretKey sk = kg.generateKey();
String secretKey = String.valueOf(Hex.encodeHex(sk.getEncoded()));
System.out.println("Secret key is " + secretKey);
return sk;
}
public static String encrypt(String strToEncrypt, SecretKey secretKey) {
try {
Cipher cipher = Cipher.getInstance("AES/ECB/PKCS5PADDING");
cipher.init(Cipher.ENCRYPT_MODE, secretKey);
encryptedString = new String(Base64.encodeBase64String(cipher.doFinal(strToEncrypt.getBytes())));
} catch (Exception e) {
System.out.println("Error while encrypting: " + e.toString());
}
return encryptedString;
}
public static String decrypt(String strToDecrypt, SecretKey secretKey) {
try {
Cipher cipher = Cipher.getInstance("AES/ECB/PKCS5PADDING");
cipher.init(Cipher.DECRYPT_MODE, secretKey);
decryptedString = new String(cipher.doFinal(Base64.decodeBase64(strToDecrypt)));
} catch (Exception e) {
System.out.println("Error while decrypting: " + e.toString());
}
return decryptedString;
}
}
输出
Secret key is 2df36561b09370637d35b4a310617e60
Encrypted String : TUDUORnWtsZFJAhBw1fYMF9CFExb/tSsLeDx++cpupI=
It should not come in new line
Decrypted String : This text has to be encrypted
其实加密后的字符串是TUDUORnWtsZFJAhBw1fYMF9CFExb/tSsLeDx++cpupI=/r/n。
我是否需要从加密字符串中显式替换 \r 和 \n 或者我在上面的代码中做错了什么?
【问题讨论】:
-
Base64 字符串中的空格被忽略。没有任何错误。虽然可能有一个 Base64 编码器选项来防止添加字符。
标签: java encryption aes newline carriage-return