如何一次将所有用户输入在一行中推送到 Python 中的链接列表？

Question

代码如下：

class Node:
    def __init__(self, data):
        self.data = data
        self.next = None


class LinkedList:
    def __init__(self):
        self.head = None
        self.last_node = None

    def prepend(self, data):
        new_node = Node(data)
        new_node.next = self.head
        self.head = new_node

    def push(self, data):
        if self.last_node is None:
            self.head = Node(data)
            self.last_node = self.head
        else:
            self.last_node.next = Node(data)
            self.last_node = self.last_node.next

    def insert_after(self, prev_node, data):
        if not prev_node:
            print('Given node not present in the list')
            return
        new_node = Node(data)
        new_node.next = prev_node.next
        prev_node.next = new_node

    def pswap(self):
        temp = self.head
        if temp is None:
            return

        while (temp is not None and temp.next is not None):
            temp.data, temp.next.data = temp.next.data, temp.data
            temp = temp.next.next

    def display(self):
        current = self.head
        while current:
            print(current.data, end=' ')
            current = current.next


llist = LinkedList()
T = int(input())
for x in range(T):
    d = int(input())
    llist.push(d)

llist.display()
llist.pswap()
print()
llist.display()

这里我可以这样通过：
4 => 您要输入的元素数
1
2
3
4
但我想以这种方式给用户输入：
4 => 您要输入的元素数
1 2 3 4

Answer 1

最简单的实现可能就是split用户提供的字符串：

llist = LinkedList()
T = int(input("Number of elements: "))
data = input("Space-separated numbers: ")
numbers = map(int, data.split())

for d in numbers:
    llist.push(d)

这会忽略用户提供的元素 T 的数量，但您可以通过要求用户输入更多数据（如果他们输入的数据不足）或通知多余的数据将不会被处理来合并此信息：

T = int(input("Number of elements: "))
data = []
while len(data) < T:
    data.extend(map(int, input("Space-separated numbers: ").split()))

if len(data) > T:
    print(f"Too much data entered, its length will be cut to {T}")

for d in data[:T]:
    llist.push(d)