为什么我的不同行字符串打印在一个块中，而不是 MIPS MARS 中的单独行？

Question

我正在使用 MIPS MARS 程序集编写一个程序，该程序集执行不同的数学计算，但我无法理解为什么 .data 部分中的字符串值在程序开头打印为块而不是单独的行.我也无法将值打印在正确的语句旁边。

 .data
   NL:  .asciiz "\n" #NL=new line varible kinda name
   addition: .ascii "The value of a + b = \n"
   subtraction: .ascii "The value of a - b = \n "
   prob_3: .ascii "The value of (a + b) - 8 =  \n"
   prob_4: .ascii "The value of (a + b) - (c + d) =  \n"
   prob_5: .ascii "The value of ((a + b) + (d - c) + 17 =  \n"

.text

  li $s0, 8
  li $s1, 8
  li $s2, 16
  li $s3, 8

  la $a0, addition 
  li $v0, 4 
  syscall 
  add $t1, $s0, $s1
  li $v0, 1
  add $a0, $t1, $zero
  syscall

  la $a0, NL
  li $v0, 4
  syscall

  la $a0, subtraction 
  li $v0, 4 
  syscall 
  sub $t2, $s0, $s1
  li $v0, 1
  sub $a0, $t2, $zero
  syscall

  la $a0, NL
  li $v0, 4
  syscall

  la $a0, prob_3 
  li $v0, 4
  syscall 
  subi $t3, $t1, 8
  li $v0, 1
  sub $a0, $t3, $zero
  syscall

  la $a0, NL
  li $v0, 4
  syscall

  la $a0, prob_4 
  li $v0, 4  
  syscall 
  add $t4, $s2, $s3
  sub $t5, $t1, $t4
  li $v0, 1
  sub $a0, $t5, $zero
  syscall

  la $a0, NL
  li $v0, 4
  syscall

  la $a0, prob_5
  li $v0, 4  
  syscall 
  sub $t6, $s3, $s2
  add $t7, $t1, $t6
  addi $t8, $t7, 17
  li $v0, 1
  add $a0, $t8, $zero
  syscall

我得到的结果：

The value of a + b = 
The value of a - b = 
The value of (a + b) - 8 =  
The value of (a + b) - (c + d) =  
The value of ((a + b) + (d - c) + 17 =  
16
The value of a - b = 
The value of (a + b) - 8 =  
The value of (a + b) - (c + d) =  
The value of ((a + b) + (d - c) + 17 =  
0
The value of (a + b) - 8 =  
The value of (a + b) - (c + d) =  
The value of ((a + b) + (d - c) + 17 =  
8
The value of (a + b) - (c + d) =  
The value of ((a + b) + (d - c) + 17 =  
-8
The value of ((a + b) + (d - c) + 17 =  
25

以及我想要得到的结果：

The value of a + b = 16
The value of a - b = 0 
The value of (a + b) - 8 = 8  
The value of (a + b) - (c + d) = -8
The value of ((a + b) + (d - c) + 17 = 25

谁能帮我解决这个问题？

Answer 1

在.data 段中定义的字符串末尾不应有换行符\n。换行符将未来的输出推送到下一行，因此您在字符串后面打印的数字将放在它后面的行上。

您还应该对这些字符串使用以空字符结尾的字符串 (.asciiz)。这就是为什么您要一次打印出所有报表的原因；代码不知道何时停止打印，因为没有终止字符。

Answer 2

更新更正代码：

.data
    NL:  .asciiz "\n" #NL=new line varible kinda name
    prob_1: .asciiz "The value of a + b = "
    prob_2: .asciiz "The value of a - b =  "
    prob_3: .asciiz "The value of (a + b) - 8 =  "
    prob_4: .asciiz "The value of (a + b) - (c + d) =  "
    prob_5: .asciiz "The value of ((a + b) + (d - c) + 17 =  "

.text

  li $s0, 8
  li $s1, 8
  li $s2, 16
  li $s3, 8

  la $a0, prob_1 
  li $v0, 4 
  syscall 
  add $t1, $s0, $s1
  li $v0, 1
  add $a0, $t1, $zero
  syscall

  la $a0, NL
  li $v0, 4
  syscall

  la $a0, prob_2 
  li $v0, 4 
  syscall 
  sub $t2, $s0, $s1
  li $v0, 1
  sub $a0, $t2, $zero
  syscall

  la $a0, NL
  li $v0, 4
  syscall

  la $a0, prob_3 
  li $v0, 4
  syscall 
  subi $t3, $t1, 8
  li $v0, 1
  sub $a0, $t3, $zero
  syscall

  la $a0, NL
  li $v0, 4
  syscall

  la $a0, prob_4 
  li $v0, 4  
  syscall 
  add $t4, $s2, $s3
  sub $t5, $t1, $t4
  li $v0, 1
  sub $a0, $t5, $zero
  syscall

  la $a0, NL
  li $v0, 4
  syscall

  la $a0, prob_5
  li $v0, 4  
  syscall 
  sub $t6, $s3, $s2
  add $t7, $t1, $t6
  addi $t8, $t7, 17
  li $v0, 1
  add $a0, $t8, $zero
  syscall