【问题标题】:Java OpenCV - Rectangle Detection with Hough TransformJava OpenCV - 使用霍夫变换进行矩形检测
【发布时间】:2016-12-09 11:09:59
【问题描述】:

我正在开发一个程序来检测矩形形状并将边界框绘制到检测到的区域。

对于边缘检测,我使用了 Canny 边缘检测。 然后,我使用霍夫变换提取线条。

这是原图 enter image description here

这是结果图片 enter image description here

我的问题是我无法在检测到的区域上绘制边界框。 看来我的程序只能检测到一条水平线。 如何检测矩形形状并将矩形线绘制到检测到的形状?

我看过类似的问题,要求找到矩形的4个角点,检查点是否为90度,然后找到交点。我真的很困惑如何在 Java opencv 中对其进行编码。检测形状并将边界框绘制到检测到的其他方法也可以。

这是代码

import org.opencv.core.Core;
import org.opencv.core.CvType;
import org.opencv.core.Mat;
import org.opencv.core.Point;
import org.opencv.core.Scalar;
import org.opencv.core.Size;
import org.opencv.imgcodecs.*;
import org.opencv.imgproc.Imgproc;

public class HoughTransformCV2 {

    public static void main(String[] args) {
        try {
            System.loadLibrary(Core.NATIVE_LIBRARY_NAME);
            Mat source = Imgcodecs.imread("rectangle.jpg", Imgcodecs.CV_LOAD_IMAGE_ANYCOLOR);
            Mat destination = new Mat(source.rows(), source.cols(), source.type());

            Imgproc.cvtColor(source, destination, Imgproc.COLOR_RGB2GRAY);
            Imgproc.equalizeHist(destination, destination);
            Imgproc.GaussianBlur(destination, destination, new Size(5, 5), 0, 0, Core.BORDER_DEFAULT);

            Imgproc.Canny(destination, destination, 50, 100);
            //Imgproc.adaptiveThreshold(destination, destination, 255, Imgproc.ADAPTIVE_THRESH_MEAN_C, Imgproc.THRESH_BINARY, 15, 40);
            Imgproc.threshold(destination, destination, 0, 255, Imgproc.THRESH_BINARY);

            if (destination != null) {
                Mat lines = new Mat();
                Imgproc.HoughLinesP(destination, lines, 1, Math.PI / 180, 50, 30, 10);
                Mat houghLines = new Mat();
                houghLines.create(destination.rows(), destination.cols(), CvType.CV_8UC1);

                //Drawing lines on the image
                for (int i = 0; i < lines.cols(); i++) {
                    double[] points = lines.get(0, i);
                    double x1, y1, x2, y2;
                    x1 = points[0];
                    y1 = points[1];
                    x2 = points[2];
                    y2 = points[3];

                    Point pt1 = new Point(x1, y1);
                    Point pt2 = new Point(x2, y2);

                    //Drawing lines on an image
                    Imgproc.line(source, pt1, pt2, new Scalar(0, 0, 255), 4);
                }

            }

            Imgcodecs.imwrite("rectangle_houghtransform.jpg", source);

        } catch (Exception e) {
            System.out.println("error: " + e.getMessage());
        }
    }
}

对 Java 的任何帮助将不胜感激 :) 非常感谢!

【问题讨论】:

    标签: java algorithm opencv image-processing object-detection


    【解决方案1】:

    您可以按以下步骤执行此操作:

    1. 在将颜色转换为灰色后,执行 canny edge。

      int 阈值 = 100;

      Imgproc.Canny(grayImage, edges, threshold, threshold*3);

    2. 现在找到边缘图像中的轮廓。

    Imgproc.findContours(edges, contours, hierarchy, Imgproc.RETR_EXTERNAL, Imgproc.CHAIN_APPROX_SIMPLE);

    1. 然后在所有轮廓上循环

    .....

    MatOfPoint2f matOfPoint2f = new MatOfPoint2f();
    MatOfPoint2f approxCurve = new MatOfPoint2f();
    
    for (int idx = 0; idx >= 0; idx = (int) hierarchy.get(0, idx)[0]) {
        MatOfPoint contour = contours.get(idx);
        Rect rect = Imgproc.boundingRect(contour);
        double contourArea = Imgproc.contourArea(contour);
        matOfPoint2f.fromList(contour.toList());
        Imgproc.approxPolyDP(matOfPoint2f, approxCurve, Imgproc.arcLength(matOfPoint2f, true) * 0.02, true);
        long total = approxCurve.total();
        if (total == 3) { // is triangle
            // do things for triangle
        }
        if (total >= 4 && total <= 6) {
            List<Double> cos = new ArrayList<>();
            Point[] points = approxCurve.toArray();
            for (int j = 2; j < total + 1; j++) {
                cos.add(angle(points[(int) (j % total)], points[j - 2], points[j - 1]));
            }
            Collections.sort(cos);
            Double minCos = cos.get(0);
            Double maxCos = cos.get(cos.size() - 1);
            boolean isRect = total == 4 && minCos >= -0.1 && maxCos <= 0.3;
            boolean isPolygon = (total == 5 && minCos >= -0.34 && maxCos <= -0.27) || (total == 6 && minCos >= -0.55 && maxCos <= -0.45);
            if (isRect) {
                double ratio = Math.abs(1 - (double) rect.width / rect.height);
                drawText(rect.tl(), ratio <= 0.02 ? "SQU" : "RECT");
            }
            if (isPolygon) {
                drawText(rect.tl(), "Polygon");
            }
        }
    }
    

    辅助方法:

    private double angle(Point pt1, Point pt2, Point pt0) {
        double dx1 = pt1.x - pt0.x;
        double dy1 = pt1.y - pt0.y;
        double dx2 = pt2.x - pt0.x;
        double dy2 = pt2.y - pt0.y;
        return (dx1*dx2 + dy1*dy2)/Math.sqrt((dx1*dx1 + dy1*dy1)*(dx2*dx2 + dy2*dy2) + 1e-10);
    }
    
    private void drawText(Point ofs, String text) {
        Imgproc.putText(colorImage, text, ofs, Core.FONT_HERSHEY_SIMPLEX, 0.5, new Scalar(255,255,25));
    }
    

    希望对你有帮助!!

    【讨论】:

    • @Bahrandum Adil 您能否说明 if 条件中的“angle”、“drawText”和“triangle”方法?我是opencv的新手,我不知道这些是库中的静态方法还是您自己实现的函数。您对 Imgproc.Canny 使用什么“阈值”?
    • @JonathanBarbero 嗨!。大多数 OpenCV 函数都是静态的。像 Imgproc 或 Core 的函数,你可以直接使用这些,只是用类名点函数名。并且答案已经更新,您可以再次查看答案。祝你好运!
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