NSKeyedArchiver - 无法识别的选择器发送到实例错误答案

【问题标题】：NSKeyedArchiver - Unrecognized selector sent to instance errorNSKeyedArchiver - 无法识别的选择器发送到实例错误
【发布时间】：2017-04-19 21:59:12
【问题描述】：

我在使用NSKeyedArchiver.archivedData 时遇到unrecognized selector sent to instance 错误。

我试图将 JSON 输出解析存储到自定义类对象，并在成功登录时将其存储在 NSUserDefaults 中。我想在其他控制器中使用这些细节来进行其他一些POST 调用。但是在将它们保存在我的LoginController 中时，我遇到了这个错误。有人可以帮忙解决这个问题吗？

我的班级：

class UserDetails : NSObject,NSCoding {


    var token:String?
    var agentId: Int?
    var userId:Int?


    //to directly get values from JSON output

    init?(user: [String: Any]) {

        guard let token = user["token"] as? String,
            let agentId = user["agent_id"] as? Int,
            let userId = user["user_id"] as? Int
        else{
            return nil
        }


                self.token = token;
                self.agentId = agentId;
                self.userId = userId;
        }

    init(pToken:String,pAgentId:Int,pUserId:Int)
    {
        token = pToken;
        agentId = pAgentId;
        userId = pUserId;
    }

    //TO SAVE IN NSUSERDEFAULTS

    required init?(coder aDecoder: NSCoder){
        self.token = aDecoder.decodeObject(forKey: "token") as? String
        self.agentId = aDecoder.decodeObject(forKey: "agentId") as? Int
        self.userId = aDecoder.decodeObject(forKey: "userId") as? Int

        return self
    }

    public func encode(with aCoder: NSCoder) {
        aCoder.encode(token,forKey:"token")
        aCoder.encode(agentId,forKey:"agentId")
    }

}

成功登录后，我将存储此详细信息。

登录视图控制器：

if let userDict = json["user"] as? [String:Any]
                        {
                            guard let userObject = UserDetails(user:userDict) else {
                                print("Failed to create user from dictionary")
                                return
                            } 
                            DispatchQueue.main.async {

                                self.saveUserItemToDefault(userObject: userObject);

                                self.dismiss(animated: true, completion: nil)
                                self.performSegue(withIdentifier: "loginSuccessIdentifier", sender: userObject)

                            }
                        }




 func saveUserItemToDefault(userObject:UserDetails) -> Void {
            let encodedToken = NSKeyedArchiver.archivedData(withRootObject: userObject.token) //error is thrown on the first archiver call
            let encodedAgentId = NSKeyedArchiver.archivedData(withRootObject: userObject.agentId)
            let encodedUserId = NSKeyedArchiver.archivedData(withRootObject: userObject.userId)

let encodedArray:[NSData] = [encodedToken as NSData,encodedAgentId as NSData,encodedUserId as NSData]

            self.prefs.set(encodedArray, forKey: "UserDetailsItem")
            self.prefs.synchronize()
        }

错误信息：

2016-12-05 18:08:57.917 ABCAPP[2800:183556] -[_SwiftValue encodeWithCoder:]: unrecognized selector sent to instance 0x600000079f00
2016-12-05 18:08:57.920 ABCAPP[2800:183556] *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '-[_SwiftValue encodeWithCoder:]: unrecognized selector sent to instance 0x600000079f00'
*** First throw call stack:
(
    0   CoreFoundation                      0x0000000104b5e34b __exceptionPreprocess + 171
    1   libobjc.A.dylib                     0x00000001045bf21e objc_exception_throw + 48
    2   CoreFoundation                      0x0000000104bcdf34 -[NSObject(NSObject) doesNotRecognizeSelector:] + 132
    3   CoreFoundation                      0x0000000104ae3c15 ___forwarding___ + 1013
    4   CoreFoundation                      0x0000000104ae3798 _CF_forwarding_prep_0 + 120
    5   Foundation                          0x00000001040f855c _encodeObject + 1263
    6   Foundation                          0x000000010412d29a +[NSKeyedArchiver archivedDataWithRootObject:] + 156
    7   ABCAPP                     0x0000000103fa8d4b _TFC15ABCAPP19LoginViewController21saveUserItemToDefaultfT10userObjectCS_11UserDetails_T_ + 235
    8   ABCAPP                     0x0000000103face3d _TFFFC15ABCAPP19LoginViewController10checkLoginFPs9AnyObject_T_U_FTGSqV10Foundation4Data_GSqCSo11URLResponse_GSqPs5Error___T_U_FT_T_ + 77
    9   ABCAPP                     0x0000000103f9d627 _TTRXFo___XFdCb___ + 39
    10  libdispatch.dylib                   0x0000000108112980 _dispatch_call_block_and_release + 12
    11  libdispatch.dylib                   0x000000010813c0cd _dispatch_client_callout + 8
    12  libdispatch.dylib                   0x000000010811c8d6 _dispatch_main_queue_callback_4CF + 406
    13  CoreFoundation                      0x0000000104b224f9 __CFRUNLOOP_IS_SERVICING_THE_MAIN_DISPATCH_QUEUE__ + 9
    14  CoreFoundation                      0x0000000104ae7f8d __CFRunLoopRun + 2205
    15  CoreFoundation                      0x0000000104ae7494 CFRunLoopRunSpecific + 420
    16  GraphicsServices                    0x000000010910da6f GSEventRunModal + 161
    17  UIKit                               0x0000000104f81f34 UIApplicationMain + 159
    18  ABCAPP                     0x0000000103faff2f main + 111
    19  libdyld.dylib                       0x000000010818868d start + 1
    20  ???                                 0x0000000000000001 0x0 + 1
)
libc++abi.dylib: terminating with uncaught exception of type NSException

【问题讨论】：

整个错误信息是什么？它可以帮助找到问题的确切位置，而不是阅读所有代码。
@Larme 添加了错误消息。请看一看。

标签： ios swift3 nsuserdefaults nskeyedarchiver

【解决方案1】：

这个问题可能是因为您尝试归档一个可选的并且Optional 没有encodeWithCoder 方法（因此出现错误消息）。

尝试这样做：

public func encode(with aCoder: NSCoder) {
        if let token = token {
            aCoder.encode(token,forKey:"token")
        }
        if let agentId = agentId {
            aCoder.encode(agentId,forKey:"agentId")
        }
    }

【讨论】：

嗨JPetric。我尝试将代码更改为您上面提到的内容。还是一样的错误。
拜托，你能不能尝试在类的声明中将token和agentId声明为String和Int（不是可选的）（var token: String而不是var token: String？）？
我试着把它改成你建议的（不是可选的）。现在它在if let token = token { aCoder.encode(token,forKey:"token")}附近抛出类似Initializer for conditional binding must have Optional type, not string的错误
从编码方法中删除 if let token = token 和 if let agentId = agentId
现在需要初始化的代码？一直在抛出错误。像self.token = aDecoder.decodeObject(forKey: "token") as? String 应该替换为(aDecoder.decodeObject(forKey: "token") as? String)!

【解决方案2】：

除了@JPetric 已经说过的话，我可能是真的，当你遇到这种异常时，一般来说，问题是你试图归档一个在 Objective-C 中无法表示的数据类型。这可以是可选的、快速枚举、快速闭包等。添加异常断点以查看无法编码的实际对象，然后找到使用 Objective-C 对象的方法。

【讨论】：

我同意。添加异常断点是必须的（stackoverflow.com/questions/17802662/…）

【解决方案3】：

连同来自JPetric 和Valentin Radu 的输入，我稍微修改了代码并消除了错误。

以下是我的解决方案：

class UserDetails : NSObject,NSCoding {

      //var token:String? 
      var token:String!

      //var agentId: Int? 
      var agentId: Int!

      //var userId:Int? 
      var userId:Int!


    //to directly get values from JSON output

    init?(user: [String: Any]) {

        guard let token = user["token"] as? String,
            let agentId = user["agent_id"] as? Int,
            let userId = user["user_id"] as? Int
        else{
            return nil
        }


                self.token = token;
                self.agentId = agentId;
                self.userId = userId;
        }

    init(pToken:String,pAgentId:Int,pUserId:Int)
    {
        token = pToken;
        agentId = pAgentId;
        userId = pUserId;
    }

    //TO SAVE IN NSUSERDEFAULTS

    required init?(coder aDecoder: NSCoder){
        self.token = aDecoder.decodeObject(forKey: "token") as? String
        self.agentId = aDecoder.decodeObject(forKey: "agentId") as? Int
        self.userId = aDecoder.decodeObject(forKey: "userId") as? Int

        return self
    }

    public func encode(with aCoder: NSCoder) {
        aCoder.encode(token,forKey:"token")
        aCoder.encode(agentId,forKey:"agentId")
    }

}

【讨论】：