遍历一个类对象的数组，并将这些元素放入一个属于另一个类对象的数组中。 [复制]

Question

假设我有两个类：

class One
  attr_reader :array
  def initialize(array)
    @array = array
  end
end

class Two < One
  attr_reader :array
  def initialize
    @array = []
  end
end

我现在实例化“One”类的一个对象和“Two”类的两个对象。

array = ["D","E"] 
a = One.new(array)
b = Two.new
c = Two.new

是否可以在 One 类中创建一个接受两个参数的方法，如果字符串存在于 One @array 中，则复制该元素并将该元素放入属于 Two 类的指定数组的数组中？

Example:

def place_string(element,location)
  if location == "b"
    take element, copy it and place it into @array in b
  elsif location == "c"
    take element, copy it and place it into @array in c
  end
end
a.place_string("D","b")
a.place_string("E","c")

Output:
  a.array = ["D","E"]
  b.array = ["D"]
  c.array = ["E"]

Answer 1

class One
  attr_reader :array
  def initialize(array=[])
    @array = array
  end

  def copy(element, location)
    if array.include? element
      location.array << element
    end
  end
end

class Two < One
end

array = ["D","E"] 
a = One.new(array)
b = Two.new
c = Two.new

a.copy("D", b)
a.copy("NOT EXIST", b)
b.array
#=> ["D"]