累积输出，好像有名字一样答案

【问题标题】：cumulative output as if with name累积输出，好像有名字一样
【发布时间】：2015-12-29 01:36:45
【问题描述】：

class Cummulative {
    public static void main(String[] args) {
        int arrayValue[] ={0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26};

        String arrayAlpha[] ={"A","A","B","C","D","E","F","G","H","I","J","K","L","M","O","P","Q","R","S","T","U","V","X","Y","Z"};

        String newArray[] = {"R","A","G","H","U"};

        int total=0;

        for (int i=0; i<newArray.length; i++) {
            for (int j=0; j<arrayAlpha.length; j++) {
                if (arrayAlpha[j].equals(arrayValue[i])) {
                    total = total+arrayValue[j];
                    System.out.println(newArray[i]+"  "+arrayValue[j]+" "+total);
                }
            }
        }
    }
}

输出应具有以下格式：

【问题讨论】：

for(int i=0;i
格式化正确的代码，这将有助于提高可见性
你到底想达到什么目的？
我认为您需要在 if 语句中将 arrayValue 替换为 newArray。
我的代码不能正常工作，它不显示任何值，第一个左侧必须显示名称 RAGHU，后面的步骤必须是实际字母值，最后的右侧必须显示累积加法值

标签： java arrays for-loop

【解决方案1】：

这是你的问题：if (arrayAlpha[j].equals(arrayValue[i]))

应该是(arrayAlpha[j].equals(newArray[i]))。

旁注：使用此代码“A”将返回 0。这似乎是不希望的，所以我从 arrayAlpha 和 arrayValue 中删除了第一个值。

class Cummulative {
    public static void main(String[] args) {
        int arrayValue[] ={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26};

        String arrayAlpha[] ={"A","B","C","D","E","F","G","H","I","J","K","L","M","O","P","Q","R","S","T","U","V","X","Y","Z"};

        String newArray[] = {"R","A","G","H","U"};

        int total=0;

        for (int i=0; i<newArray.length; i++) {
            for (int j=0; j<arrayAlpha.length; j++) {
                if (arrayAlpha[j].equals(newArray[i])) {
                    total += arrayValue[j];
                    System.out.println(newArray[i]+"  "+arrayValue[j]+" "+total);
                }
            }
        }
    }
}

【讨论】：

@Alex 没问题！请考虑在我的答案旁边打灰色复选标记:)