用数组值替换字符串中的整数以对应顺序

Question

我有一个字符串，我想用我的数组值替换整数（数字），以便按照对应顺序排列，字符串可以有不同的数学符号，具体取决于用户如何捕获数据。我可以有一个字符串和一个数组，例如：

var myArray = [
    "John",
    "London", 
    "March", 
    "Year 2017", 
    "My Age", 
    "We will meet", 
    "Next year", 
    "Year end"];

var testString = "234 == 123 AND 346 == 378 OR 123 >= 236 AND 124 != 478";

我希望结果是这样的字符串：

"John == London AND March == Year 2017 OR My Age >= We will meet AND Next year != Year end"

查看下面的代码并帮助解决我哪里出错了。

var myArray = ["John", "London", "March", "Year 2017", "My Age", "We will meet", "Next year", "Year end"];
var testString = "234 == 123 AND 346 == 378 OR 123 >= 236 AND 124 != 478";

var partsA = testString.split(" AND ");
console.log("A:", partsA);
var partsB = [];
var newString = "";
$.each(partsA, function(k, v) {
    partsB = v.split(" == ");
    console.log("B-1:", partsB);
    if (!isNaN(partsB[0])) {
        partsB[0] = myArray[parseInt(partsB[0])];
    }
    if (!isNaN(partsB[1])) {
        partsB[1] = myArray[parseInt(partsB[1])];
    }
    console.log("B-2:", partsB);
    partsA[k] = partsB.join(" == ");
});
newString = partsA.join(" AND ");
console.log("S:", newString);
$("#newstring").text(newString);

Answer 1

如果您想将myArray 数组中的所有numbers 替换为它们各自的strings，将string 替换为相同的index，您可以执行以下操作：

var matches = testString.match(/\d+/g);
var result = testString;
matches.forEach(function(str, index) {
  result = result.replace(str, myArray[index]);
});

• 使用.match(/\d+/) 将所有数字放入matches 数组中。
• 然后循环遍历这个匹配数组并将每个数字替换为其 与您的 myArrayvariable 中的 string 匹配。

它会给你以下结果：

John == London AND March == Year 2017 OR My Age >= We will meet AND Next year != Year end

演示：

var myArray = ["John", "London", "March", "Year 2017", "My Age", "We will meet", "Next year", "Year end"];
var testString = "234 == 123 AND 346 == 378 OR 123 >= 236 AND 124 != 478";

var matches = testString.match(/\d+/g);
var result = testString;
matches.forEach(function(str, index) {
  result = result.replace(str, myArray[index]);
});
console.log(result);