【发布时间】:2025-12-11 20:50:01
【问题描述】:
我想比较两个数组并将数组值替换为相同的属性值。
let first_array =[{ model: 'aa', size: '85(XS)', count: 200, number: '10-2' },{ model: 'bb', size: '105(XL)', count: 150, number: '' },{ model: 'cc', size: '95(M)', count: 100, number: '9-2' },{ model: 'dd', size: '85(XS)', count: 50, number: '' }]
let second_array = [{ model: 'aa', size: '85(XS)', count: 1, number: '' },{ model: 'bb', size: '105(XL)', count: 1, number: '' },{ model: 'cc', size: '95(M)', count: 2, number: '' },{ model: 'dd', size: '85(S)', count: 3, number: '' },{ model: 'dd', size: '80(XS)', count: , number: '' }]
假设有两个数组。 比较'a'和'b'数组,和'model'一样的'size'把'a'数组的count值插入到'b'数组的count值中,错误的标记为null .
这就是我想要的。
let vlaue = [{ model: 'aa', size: '85(XS)', count: 200, number: '10-2' },{ model: 'bb', size: '105(XL)', count: 150, number: '' },{ model: 'cc', size: '95(M)', count: 100, number: '9-2' },{ model: 'dd', size: '85(XS)', count: 50, number: '' }]
这是我试过的代码。
for (var j = 0; j<second_array.length;j++){
for(var i = 0; i < first_array.length ;i++){
var count = false
if(second_array[j]["model"]+second_array[j]["size"] === first_array[i]){
count = true
}else{
count = false
}
if(count == true){
if(objectdata[first_array[i]]["count"] === 0){
second_array[j]["count"] = ""
second_array[j]["number"] = ""
}else{
second_array[j]["count"] = objectdata[first_array[i]]["count"];
second_array[j]["number"] = objectdata[first_array[i]]["number"];
}
break
}else{
second_array[j]["count"] = ""
second_array[j]["number"] = ""
}
} }
【问题讨论】:
标签: javascript arrays sorting arraylist