如何创建一个检查对象 javascript 数组中的布尔字段的函数

Question

最终目标：如果所有字段都是true最后一个object.field必须改为true

const badges = [

  { name: "peter", given : true, points: 10 },
    { name: "Alice", given : true,  points: 100 },
    { name: "Hugo", given: true,  points: 100 },
    { name: "Salah", given: false,  points: 500 },
    { name: "Rui", given: false, points: 1000 },
    { name: "Jimena", given: false,  points: 10000 }

]

我的代码：

const badges = [
    { name: "peter", given : true, points: 10 },
    { name: "Alice", given : true,  points: 100 },
    { name: "Hugo", given: true,  points: 100 },
    { name: "Salah", given: false,  points: 500 },
    { name: "Rui", given: false, points: 1000 },
    { name: "Jimena", given: false,  points: 10000 }
]

let count = 0
badges.forEach((ele, index) => {
  const l = badges.length
  ele.given === true ? count = count + 1 : count
  count == l - 1 ? badges[l - 1].given = true : badges[l - 1].given
})

console.log(badges)

我想要实现的目标： 是一个更通用的函数，可以在任何地方工作，但我找不到方法，或者可能是最简单的方法。

Answer 1

只要提供的field 是布尔值，这将起作用。使用slice 获取除最后一个元素之外的所有元素，使用every 检查所有元素是否符合条件。

const badges = [

  { name: "peter", given : true, points: 10 },
    { name: "Alice", given : true,  points: 100 },
    { name: "Hugo", given: true,  points: 100 },
    { name: "Salah", given: true,  points: 500 },
    { name: "Rui", given: true, points: 1000 },
    { name: "Jimena", given: false,  points: 10000 }

]

function check(input, field) {
  var result = input.slice(0,input.length-1).every(x => x[field]);
  if(result) {
    badges[input.length-1][field] = true;
  }
}

check(badges,"given");
console.log(badges)