PHP，搜索和替换字符串内的数组元素[关闭]

Question

我尝试在字符串中搜索和替换数组元素，但不知道该怎么做！ 我的代码前：

$string_text = 'some random text with random lenght ';

function check_strings($string_text){

$new_string_text = $string_text; //random text with randon lenght 
$array_of_3000 = ['some','text','hello','no','why','oh','random']; // array with lenght of 3000
$text_tokens = explode($new_string_text,' '); // to make it array 
foreach($text_tokens as $token_index =>$token ){  // loop on $text_tokens 
    if (in_array($token, $array_of_3000)){   // if token in $array_of_3000 -> change token with link 

        $token_link = sprintf("<a href='<?php echo site_url('/%s'); ?>' >  %s </a>",$tokens,$tokens); // changeing $token to  html link 
        // update $new_string_text , $token with -> $token_link 
        $new_string_text = str_replace($tokens,$token_link,$tokens);


    }
}
    return $new_string_text;
}
 //  text =  'some random text with random lenght ' -> same , text , random x2 are in $array_of_3000 so need to change them with html link 
    // random x2 -> if find more as 1 just link 1 of them 
    // " <a href='<?php echo site_url('/some'); ?>' >  some </a>"
    // " <a href='<?php echo site_url('/text '); ?>' >  text </a>"
    // " <a href='<?php echo site_url('/random '); ?>' >  random </a>" 
// output -> all words in input string if can finded in $array_of_3000 need change with it link 
   
   

if 语句 (in_array()) 不起作用，我不知道如何找到匹配词 我该怎么做 ？ 感谢您的帮助:)

感谢我修复它的每一个人 代码现在可以正常工作了```

        if (in_array($token, $array_of_words)){   // if token in $array_of_3000 -> change token with link 
    
            $token_link = sprintf("<a   href='<?php echo site_url('/%s'); ?>' >  %s </a>",$tokens,$tokens); // changeing $token to  html link 
            // update $new_string_text , $token with -> $token_link 
            $new_string_text = str_replace($tokens,$token_link,$tokens);
    
    
        }
    }

Answer 1

可以使用phpstr_replace (php manual)函数

str_replace 接受参数中的数组

示例：

$str= 'random text idk';
$tokens = ['random', 'idk'];
$newTokens = ['token1', 'token2'];

$str = str_replace($tokens, $newTokens, $str));
// value of str: "token1 text token2"

对于您的示例，您可以使用它

function check_strings($string_text){
    $array_of_3000 = ['some', 'text', 'hello', 'no', 'why', 'oh', 'random'];
    $array_of_3000_replacements = [];
        
    foreach ($array_of_3000 as $oldToken) {
        $array_of_3000_replacements[] = sprintf("<a href='<?php echo site_url('/%s'); ?>' >  %s </a>", $oldToken, $oldToken);
    }

    return str_replace($array_of_3000, $array_of_3000_replacements, $string_text);
}