用数组中的每一行查找段落类中的某些单词

Question

我一直在尝试制作一个简单的菜单，用户可以在其中输入要添加到段落中的行，然后搜索他们输入的单词。 但是，在搜索单词的情况下（案例 3），如果他们搜索的单词不在第一行，它就不起作用（我没有收到错误），但我的代码在一个单独的文件中使用手动输入工作。

这是我的课

public class Paragraph {

String[] lines;
int lineCount;
public Paragraph(String[]lines,int lineCount) {
    this.lines = lines;
    this.lineCount = lineCount;
    
}   
public static void main(String[] args) {
    int lineCount=0 , i = 0;
    String[] lines = new String[10];
    String curline ,search; 
    boolean loop= true; 

    Paragraph parag = new Paragraph(lines, lineCount);

    while(loop) {       
        Scanner myScanner = new Scanner(System.in);
        System.out.println();
        System.out.printf("%s\n","1) Enter a new line");
        System.out.printf("%s\n","2) Display the paragraph");           
        System.out.printf("%s\n","3) Search for word");
        System.out.printf("%s\n","4) Exit");
        int choice= myScanner.nextInt();

        myScanner.nextLine();
        switch(choice) {
        case 1:
            System.out.println("Enter your line:");
            curline = myScanner.nextLine();
            lineCount = i;
            System.out.println("Done!!");
            parag.lines[i] =  curline + " ";
            parag.lineCount = i;
            i++;
            break;
        case 2:
            int index;
            for(index=0;  index<i; index++) {
                System.out.printf("(%d) %s\n",index+1, lines[index]);
                }   
            break;

        case 3:
            System.out.println("Enter pharese to be searched:");
            search = myScanner.nextLine();
            String toBeSearched = search;
            String[] divide = toBeSearched.split(" ");
                
                for(int i1 = 0; i1 < divide.length ; i1 ++) {
                    String word = divide[i1];
                    for(int y = 0; y < lineCount; y++) {
                        if(lines[y].contains(word)) {
                            System.out.println(word + " found at line: "+ y);
                        }
                    }
                }
            break;
        case 4:
            loop = false;
            }
        }
    }
}

我在想我在案例 1 中采用线的方式可能会导致问题，但这是我测试案例 3 的另一个文件，它在这里不起作用

这是我测试案例 3 的单独文件

public static void main(String[] args) {
       
        String toBeSearched;
        boolean intIndex = false ;
        String paragraph[] = {"Hello my name is","Jack the reaper", "what up"};
        System.out.printf("enter string:");
        Scanner myScanner = new Scanner(System.in);
        toBeSearched = myScanner.nextLine();
       
    String[] divide = toBeSearched.split(" ");
   
    for(int i = 0; i < divide.length ; i ++) {
        String word = divide[i];
        for(int y = 0; y < paragraph.length ; y++) {
            if(paragraph[y].contains(word)) {
                System.out.println(word + " found at line: "+ y);
            }
        }
        
    }
}

当我在这里搜索“Hello Jack”时，它给了我

你好在第 0 行找到 杰克在第 1 行找到

但在我上面的课程中它没有任何想法？

Answer 1

for(int j = 0; j <3 ; j++) {
   paragraph[j] ="Hello my name is" ;
}

这段代码改变了你的paragraph。因此，您在

中搜索"Hello Jack"

{ "Hello my name is",
  "Hello my name is",
  "Hello my name is" }

请删除 for 循环，然后重试。

编辑：您的程序适用于您在我的计算机上提供的输入，无法重现错误。确保编译/运行正确的代码。

编辑 2：您有索引问题。请看下面的代码；

// When you enter the first line...
case 1:
    System.out.println("Enter your line:");
    curline = myScanner.nextLine();
    lineCount = i; // i is 0, but we have 1 line
    System.out.println("Done!!");
    parag.lines[i] = curline + " "; // parag[0] is set, correct
    parag.lineCount = i; // i is 0, but we have 1 line
    i++;
    break;

应该是：

case 1:
    System.out.println("Enter your line:");
    curline = myScanner.nextLine();
    System.out.println("Done!!");
    parag.lines[i] = curline + " "; // parag[0] is set, correct
    i++;
    parag.lineCount = i; // i is 1, correct
    lineCount = i; // i is 1, correct
    break;